zoukankan      html  css  js  c++  java
  • 【leetcode】1488. Avoid Flood in The City

    题目如下:

    Your country has an infinite number of lakes. Initially, all the lakes are empty, but when it rains over the nth lake, the nth lake becomes full of water. If it rains over a lake which is full of water, there will be a flood. Your goal is to avoid the flood in any lake.

    Given an integer array rains where:

    • rains[i] > 0 means there will be rains over the rains[i] lake.
    • rains[i] == 0 means there are no rains this day and you can choose one lake this day and dry it.

    Return an array ans where:

    • ans.length == rains.length
    • ans[i] == -1 if rains[i] > 0.
    • ans[i] is the lake you choose to dry in the ith day if rains[i] == 0.

    If there are multiple valid answers return any of them. If it is impossible to avoid flood return an empty array.

    Notice that if you chose to dry a full lake, it becomes empty, but if you chose to dry an empty lake, nothing changes. (see example 4)

    Example 1:

    Input: rains = [1,2,3,4]
    Output: [-1,-1,-1,-1]
    Explanation: After the first day full lakes are [1]
    After the second day full lakes are [1,2]
    After the third day full lakes are [1,2,3]
    After the fourth day full lakes are [1,2,3,4]
    There's no day to dry any lake and there is no flood in any lake.
    

    Example 2:

    Input: rains = [1,2,0,0,2,1]
    Output: [-1,-1,2,1,-1,-1]
    Explanation: After the first day full lakes are [1]
    After the second day full lakes are [1,2]
    After the third day, we dry lake 2. Full lakes are [1]
    After the fourth day, we dry lake 1. There is no full lakes.
    After the fifth day, full lakes are [2].
    After the sixth day, full lakes are [1,2].
    It is easy that this scenario is flood-free. [-1,-1,1,2,-1,-1] is another acceptable scenario.
    

    Example 3:

    Input: rains = [1,2,0,1,2]
    Output: []
    Explanation: After the second day, full lakes are  [1,2]. We have to dry one lake in the third day.
    After that, it will rain over lakes [1,2]. It's easy to prove that no matter which lake you choose to dry in the 3rd day, 
    the other one will flood.

    Example 4:

    Input: rains = [69,0,0,0,69]
    Output: [-1,69,1,1,-1]
    Explanation: Any solution on one of the forms [-1,69,x,y,-1], [-1,x,69,y,-1] or [-1,x,y,69,-1] is acceptable where 1 <= x,y <= 10^9
    

    Example 5:

    Input: rains = [10,20,20]
    Output: []
    Explanation: It will rain over lake 20 two consecutive days. There is no chance to dry any lake.

    Constraints:

    • 1 <= rains.length <= 10^5
    • 0 <= rains[i] <= 10^9

    解题思路:遍历rains,保存每个0出现的日期,同时记录已经灌满水的湖的下标以及对应的日期。遇到雨天时,先判断下雨的湖是否已满。如果已满,则根据之前灌满水的日期,找出离其最接近的后面的排水日期做排水操作即可。如果找不到,则返回[]。

    代码如下:

    class Solution(object):
        def avoidFlood(self, rains):
            """
            :type rains: List[int]
            :rtype: List[int]
            """
            import bisect
            dry = []
            res = [-1] * len(rains)
            full = {}
            for i in range(len(rains)):
                if rains[i] == 0:
                    dry.append(i)
                    continue
                elif rains[i] not in full:
                    full[rains[i]] = i
                    continue
                elif len(dry) == 0:
                    return []
    
                inx = bisect.bisect_left(dry,full[rains[i]])
                if inx == len(dry) :return []
                res[dry.pop(inx)] = rains[i]
                full[rains[i]] = i
    
            for i in dry:
                res[i] = 1
            return res
  • 相关阅读:
    datasnap 2010 为DataSnap系统服务程序添加描述
    uLanguage.pas
    cxgrid上如何取FOOTER上合计的值
    cxgrid经典用法
    datasnap 2010 DataSnap服务端和客户端发布分发方法
    php_network_getaddresses: getaddrinfo failed 原因
    查看crontab运行状态
    laravel 开启定时任务需要操作
    解决cron不执行的问题
    UPdate语句
  • 原文地址:https://www.cnblogs.com/seyjs/p/13217686.html
Copyright © 2011-2022 走看看