zoukankan      html  css  js  c++  java
  • 【leetcode】1475. Final Prices With a Special Discount in a Shop

    题目如下:

    Given the array prices where prices[i] is the price of the ith item in a shop. There is a special discount for items in the shop, if you buy the ith item, then you will receive a discount equivalent to prices[j] where j is the minimum index such that j > i and prices[j] <= prices[i], otherwise, you will not receive any discount at all.

    Return an array where the ith element is the final price you will pay for the ith item of the shop considering the special discount.

    Example 1:

    Input: prices = [8,4,6,2,3]
    Output: [4,2,4,2,3]
    Explanation: 
    For item 0 with price[0]=8 you will receive a discount equivalent to prices[1]=4, therefore, the final price you will pay is 8 - 4 = 4. 
    For item 1 with price[1]=4 you will receive a discount equivalent to prices[3]=2, therefore, the final price you will pay is 4 - 2 = 2. 
    For item 2 with price[2]=6 you will receive a discount equivalent to prices[3]=2, therefore, the final price you will pay is 6 - 2 = 4. 
    For items 3 and 4 you will not receive any discount at all.
    

    Example 2:

    Input: prices = [1,2,3,4,5]
    Output: [1,2,3,4,5]
    Explanation: In this case, for all items, you will not receive any discount at all.
    

    Example 3:

    Input: prices = [10,1,1,6]
    Output: [9,0,1,6] 

    Constraints:

    • 1 <= prices.length <= 500
    • 1 <= prices[i] <= 10^3

    解题思路:因为prices.length最大只有500,所以O(n^2)的时间复杂度完全可以接受。

    代码如下:

    class Solution(object):
        def finalPrices(self, prices):
            """
            :type prices: List[int]
            :rtype: List[int]
            """
            res = []
            for i in range(len(prices)):
                discount = 0
                for j in range(i+1,len(prices)):
                    if prices[i] >= prices[j]:
                        discount = prices[j]
                        break
                res.append(prices[i] - discount)
            return res
  • 相关阅读:
    Windows Console 程序中定时器的使用
    AT91SAM7SE应用 IRQ
    AT91SAM7SE应用 PIT 周期中断(1ms)
    AT91SAM7SE应用 UART
    Modelsim图像处理算法的仿真——图像数据操作
    按照一定的间隔,从视频中截图并保存(OpenCV)
    MacBook Pro下关闭全局网络代理
    jmeter的HTTP取样器设置重连的次数
    【C#】比较 Random 与 RandomNumberGenerator 生成随机字符串
    KendoGrid基础
  • 原文地址:https://www.cnblogs.com/seyjs/p/13585541.html
Copyright © 2011-2022 走看看