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  • 【leetcode】1662. Check If Two String Arrays are Equivalent

    题目如下:

    Given two string arrays word1 and word2, return true if the two arrays represent the same string, and false otherwise.

    A string is represented by an array if the array elements concatenated in order forms the string.

    Example 1:

    Input: word1 = ["ab", "c"], word2 = ["a", "bc"]
    Output: true
    Explanation:
    word1 represents string "ab" + "c" -> "abc"
    word2 represents string "a" + "bc" -> "abc"
    The strings are the same, so return true.

    Example 2:

    Input: word1 = ["a", "cb"], word2 = ["ab", "c"]
    Output: false
    

    Example 3:

    Input: word1  = ["abc", "d", "defg"], word2 = ["abcddefg"]
    Output: true

    Constraints:

    • 1 <= word1.length, word2.length <= 103
    • 1 <= word1[i].length, word2[i].length <= 103
    • 1 <= sum(word1[i].length), sum(word2[i].length) <= 103
    • word1[i] and word2[i] consist of lowercase letters.

    解题思路:有什么可说的呢?

    代码如下:

    class Solution(object):
        def arrayStringsAreEqual(self, word1, word2):
            """
            :type word1: List[str]
            :type word2: List[str]
            :rtype: bool
            """
            return ''.join(word1) == ''.join(word2)
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  • 原文地址:https://www.cnblogs.com/seyjs/p/14931525.html
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