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  • 【leetcode】1663. Smallest String With A Given Numeric Value

    题目如下:

    The numeric value of a lowercase character is defined as its position (1-indexed) in the alphabet, so the numeric value of a is 1, the numeric value of b is 2, the numeric value of c is 3, and so on.

    The numeric value of a string consisting of lowercase characters is defined as the sum of its characters' numeric values. For example, the numeric value of the string "abe" is equal to 1 + 2 + 5 = 8.

    You are given two integers n and k. Return the lexicographically smallest string with length equal to n and numeric value equal to k.

    Note that a string x is lexicographically smaller than string y if x comes before y in dictionary order, that is, either x is a prefix of y, or if i is the first position such that x[i] != y[i], then x[i] comes before y[i] in alphabetic order.

    Example 1:

    Input: n = 3, k = 27
    Output: "aay"
    Explanation: The numeric value of the string is 1 + 1 + 25 = 27, and it is the smallest string with such a value and length equal to 3.
    

    Example 2:

    Input: n = 5, k = 73
    Output: "aaszz"

    Constraints:

    • 1 <= n <= 105
    • n <= k <= 26 * n

    解题思路:贪心算法, 每一位先用a尝试,如果剩余部分全部用z的话所组成的和扔小于k,接下来尝试b,c....只能找出满足条件的值为止。

    代码如下:

    class Solution(object):
        def getSmallestString(self, n, k):
            """
            :type n: int
            :type k: int
            :rtype: str
            """
            res = ''
            alphabet = [''] + [chr(i) for i in range(97,123)]
            while n > 0:
                if (n - 1) * 26 >= k:
                    res += 'a'
                    k -= 1
                else:
                    val = k - (n - 1) * 26
                    res += alphabet[val]
                    k -= val
                n -= 1
            return res
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  • 原文地址:https://www.cnblogs.com/seyjs/p/14931536.html
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