for (int x = 0; x < 60; x++)//x是压测多少秒
{
for (int j = 0; j < 100; j++)//j是并发数
{
Task.Run(async () =>
{
//for (int i = 0; ; i++)
for (int i = 0; i < 100; i++)//i是每个并发下执行多少次如果压测行为是起task的每秒钟的并发就是i*j
{
{
DateTime tt1 = DateTime.Now;
Task.Run(() =>
{
//压测行为
});
double time = (DateTime.Now - tt1).TotalMilliseconds;
if (time < 1000)
{
await Task.Delay((int)(1000 - time));
}
}
}
});
}
System.Threading.Thread.Sleep(1000);
break;
}