java8策略模式

1.针对一段逻辑，用传统的if...else...

/**
     * 传统的 if else 解决方法
     */
    public String getCheckResult(String order) {
        if ("校验1".equals(order)) {
            return "执行业务逻辑1";
        } else if ("校验2".equals(order)) {
            return "执行业务逻辑2";
        }else if ("校验3".equals(order)) {
            return "执行业务逻辑3";
        }else if ("校验4".equals(order)) {
            return "执行业务逻辑4";
        }else if ("校验5".equals(order)) {
            return "执行业务逻辑5";
        }else if ("校验6".equals(order)) {
            return "执行业务逻辑6";
        }else if ("校验7".equals(order)) {
            return "执行业务逻辑7";
        }else if ("校验8".equals(order)) {
            return "执行业务逻辑8";
        }else if ("校验9".equals(order)) {
            return "执行业务逻辑9";
        }
        return "不在处理的逻辑中返回业务错误";
    }

2.使用策略模式改进

public class BizService3 {

    private BizUnitService bizUnitService = new BizUnitService();

    private Map<String, Function<String, String>> checkResultDispatcherComX = new HashMap<>();

    @Test
    public void test1(){
        checkResultDispatcherComXInit();
        System.out.println(getCheckResultComX("订单", 1));
    }

    /**
     * 初始化 业务逻辑分派Map 其中value 存放的是 lambda表达式
     */
    public void checkResultDispatcherComXInit() {
        checkResultDispatcherComX.put("key_订单1", order -> bizUnitService.bizOne(order));
        checkResultDispatcherComX.put("key_订单1_订单2", order -> bizUnitService.bizTwo(order));
        checkResultDispatcherComX.put("key_订单1_订单2_订单3", order -> bizUnitService.bizThree(order));
    }

    public String getCheckResultComX(String order, int level) {
        //写一段生成key的逻辑：
        String ley = getDispatcherComXKey(order, level);
        Function<String, String> result = checkResultDispatcherComX.get(ley);
        if (result != null) {
            //执行这段表达式获得String类型的结果
            return result.apply(order);
        }
        return "不在处理的逻辑中返回业务错误";
    }

    /**
     * 判断条件方法
     */
    private String getDispatcherComXKey(String order, int level) {
        StringBuilder key = new StringBuilder("key");
        for (int i = 1; i <= level; i++) {
            key.append("_" + order + i);
        }
        return key.toString();
    }

}

public class BizUnitService {

    public String bizOne(String order) {
        return order + "各种花式操作1";
    }
    public String bizTwo(String order) {
        return order + "各种花式操作2";
    }
    public String bizThree(String order) {
        return order + "各种花式操作3";
    }

}

易读，易扩展