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  • DQL查询语句内容整理

    select * from t_hq_ryxx;
    
    select bianh,xingm from t_hq_ryxx;
    
    --为字段名定义别名
    select bianh as 编号,xingm as 姓名 from t_hq_ryxx;
    
    select bianh  编号 from t_hq_ryxx;
    
    select bianh || xingm as 编号和姓名 from t_hq_ryxx;
    
    select bianh as bh, t.* from t_hq_ryxx t order by bianh desc;
    
    --order by 排序,desc降序排序
    select bianh as bh, t.* from t_hq_ryxx t order by xingb desc,bum desc;
    
    --nulls last/first的用法,desc或者asc要放在nulls前面
    select bianh ,xingm ,bum,xingb from t_hq_ryxx t order by bum desc nulls last,xingb;
    
    --选择排序为8的字段
    select * from t_hq_ryxx order by 8;
    
    --由bum和bianh列来定义排序方式
    select * from t_hq_ryxx order by bum || bianh;
    --相加的字段若有空则结果为空
    select * from t_hq_ryxx order by nianl + gongz;
    
    select nianl,gongz, (nianl + gongz) as g from t_hq_ryxx order by (nianl + gongz) desc;
    --为字段的和定义别名,并以此为排序定义方式
    select nianl,gongz, (nianl + gongz) as g from t_hq_ryxx order by g;
    
    
    select * from t_hq_ryxx;
    --选择bum为102或者103,性别为女的行
    select * from t_hq_ryxx where (bum = '102' or bum = '103') and xingb = 2;
    --选择bum不为空的行
    select * from t_hq_ryxx where bum is not null;
    
    
    --去重复
    select distinct bum,xingb from t_hq_ryxx;
    
    --模糊查询 % 通配符 _  通配一位
    select * from t_hq_ryxx where xingm like '%阿%';
    
    select * from t_hq_ryxx where bianh in ('101','103','105');
    
    select * from t_hq_ryxx where bianh = '101' or bianh = '103' or bianh = '105';
    
    select * from t_hq_ryxx where gongz between '1000' and '2000';
    
    select * from t_hq_ryxx where gongz >= 1000 and gongz <= 2000;
    
    --子查询
    select * from t_hq_ryxx where bum in (select bumenbm from t_hq_bm where lianxidh = '911');
    
    select * from t_hq_ryxx where gongz > all (select pingjgz from t_hq_bm);
    
    --分组-
    select bum, count(1) as 数量 from t_hq_ryxx group by bum;
    
    select bum, count(1) as 数量,avg(gongz) as 平均值,sum(gongz) as 合计 from t_hq_ryxx group by bianh, bum;
    --分组基础上过滤
    select bum, count(1) as 数量,avg(gongz) as 平均值,sum(gongz) as 合计 from t_hq_ryxx group by bum having avg(gongz) > 2000;
    
    select bum, count(1) as 数量,avg(gongz) as 平均值,sum(gongz) as 合计 from t_hq_ryxx where bum is not null group by bum having avg(gongz) > 2000;
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  • 原文地址:https://www.cnblogs.com/shadowduke/p/4915695.html
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