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  • 算法Sedgewick第四版-第1章基础-014一用stack把前置表达式转为后置表达式并计算值

    1.

     1 /*************************************************************************
     2  *  Exercise 1.3.10
     3  *  
     4  *  % java InfixToPostfix
     5  *  ( 1 + ( ( 2 + 3 ) * ( 4 * 5 ) ) )
     6  *  1 2 3 + 4 5 * * +
     7  *  
     8  *  % java InfixToPostfix
     9  *  ( sqrt ( 1 + 2 ) )
    10  *  1 2 + sqrt
    11  *  
    12  *************************************************************************/
    13 
    14 public class InfixToPostfix
    15 {
    16     public static void main(String[] args)
    17     {
    18         Stack<String> ops  = new Stack<String>();
    19         Stack<String> vals = new Stack<String>();
    20 
    21         while (!StdIn.isEmpty())
    22         {
    23             String s = StdIn.readString();
    24             
    25             if      (s.equals("("))               ;
    26             else if (s.equals("+") ||
    27                      s.equals("-") ||
    28                      s.equals("*") ||
    29                      s.equals("/") ||
    30                      s.equals("sqrt")) ops.push(s);
    31             else if (s.equals(")"))
    32             {
    33                 String op = ops.pop();
    34                 String v = vals.pop();
    35                 
    36                 if (op.equals("+") ||
    37                     op.equals("-") ||
    38                     op.equals("*") ||
    39                     op.equals("/"))
    40                     v = String.format("%s %s %s", vals.pop(), v, op);
    41                 else if (op.equals("sqrt"))
    42                     v = String.format("%s %s", v, op);
    43                 
    44                 vals.push(v);
    45             }
    46             else vals.push(s);
    47         }
    48         
    49         StdOut.println(vals.pop());
    50     }
    51 }

    2.

     1 /*************************************************************************
     2  *  Exercise 1.3.11
     3  *  
     4  *  % java EvaluatePostfix
     5  *  1 2 3 + 4 5 * * +
     6  *  101.0
     7  *  
     8  *  % java EvaluatePostfix
     9  *  1 5 sqrt + 2.0 /
    10  *  1.618033988749895
    11  *  
    12  *  % java EvaluatePostfix
    13  *  12 9 - 105 7 / *
    14  *  45.0
    15  *  
    16  *  % java InfixToPostfix | java EvaluatePostfix
    17  *  ( 1 + ( ( 2 + 3 ) * ( 4 * 5 ) ) )
    18  *  101.0
    19  *  
    20  *  % java InfixToPostfix | java EvaluatePostfix
    21  *  ( ( 1 + sqrt ( 5 ) ) / 2.0 )
    22  *  1.618033988749895
    23  *  
    24  *************************************************************************/
    25 
    26 public class EvaluatePostfix
    27 {
    28     public static void main(String[] args)
    29     {
    30         Stack<Double> vals = new Stack<Double>();
    31 
    32         while (!StdIn.isEmpty())
    33         {
    34             String s = StdIn.readString();
    35             
    36             if      (s.equals("(") ||
    37                      s.equals(")")) ;
    38             else if (s.equals("+") ||
    39                      s.equals("-") ||
    40                      s.equals("*") ||
    41                      s.equals("/") ||
    42                      s.equals("sqrt"))
    43             {
    44                 double v = vals.pop();
    45                 
    46                 if      (s.equals("+"))    v = vals.pop() + v;
    47                 else if (s.equals("-"))    v = vals.pop() - v;
    48                 else if (s.equals("*"))    v = vals.pop() * v;
    49                 else if (s.equals("/"))    v = vals.pop() / v;
    50                 else if (s.equals("sqrt")) v = Math.sqrt(v);
    51                 
    52                 vals.push(v);                
    53             }
    54             else
    55                 vals.push(Double.parseDouble(s));
    56         }
    57         
    58         StdOut.println(vals.pop());
    59     }
    60 }
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  • 原文地址:https://www.cnblogs.com/shamgod/p/5409056.html
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