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  • [Luogu] 魔法树

    https://www.luogu.org/problemnew/show/P3833

    树链剖分 + 线段树

    为啥会RE?? 不解

    #include <iostream>
    #include <cstdio>
    
    using namespace std;
    const int N = 1e5 + 10;
    
    #define LL long long
    
    int n, T, now = 1, tim;
    int top[N], tree[N], lst[N], rst[N], bef[N], size[N], fa[N], deep[N], son[N];
    LL W[N << 2], F[N << 2], S[N << 2];
    struct Node {int v, nxt;} G[N << 1];
    int head[N];
    LL Answer;
    
    #define gc getchar()
    
    inline int read() {
        int x = 0; char c = gc;
        while(c < '0' || c > '9') c = gc;
        while(c >= '0' && c <= '9') x = x * 10 + c - '0', c = gc;
        return x;
    }
    
    inline void Add(int u, int v) {G[now].v = v; G[now].nxt = head[u]; head[u] = now ++;}
    
    struct Node_1 {
        #define lson jd << 1
        #define rson jd << 1 | 1
        void Build_tree(int l, int r, int jd) {
            S[jd] = r - l + 1;
            if(l == r) return ;
            int mid = (l + r) >> 1;
            Build_tree(l, mid, lson);
            Build_tree(mid + 1, r, rson);
        }
        void Down(int jd) {
            int f = F[jd];
            F[lson] += f; F[rson] += f;
            W[lson] += S[lson] * f; W[rson] += S[rson] * f;
            F[jd] = 0;
        }
        void Sec_G(int l, int r, int jd, int x, int y, int yj) {
            if(x <= l && r <= y) {
                F[jd] += yj; W[jd] += S[jd] * yj; return ;
            }
            if(F[jd]) Down(jd);
            int mid = (l + r) >> 1;
            if(x <= mid) Sec_G(l, mid, lson, x, y, yj);
            if(y > mid ) Sec_G(mid + 1, r, rson, x, y, yj);
            W[jd] = W[lson] + W[rson];
        }
        void Sec_A(int l, int r, int jd, int x, int y) {
            if(x <= l && r <= y) {
                Answer += W[jd]; return ;
            }
            if(F[jd]) Down(jd);
            int mid = (l + r) >> 1;
            if(x <= mid) Sec_A(l, mid, lson, x, y);
            if(y > mid ) Sec_A(mid + 1, r, rson, x, y);
        }
    }Seg_tree;
    
    void Dfs_1(int u, int f_, int dep) {
        fa[u] = f_; deep[u] = dep; size[u] = 1;
        for(int i = head[u]; ~ i; i = G[i].nxt) {
            int v = G[i].v;
            if(v != f_) {
                Dfs_1(v, u, dep + 1);
                size[u] += size[v];
                if(size[son[u]] < size[v]) son[u] = v;
            }
        }
    }
    
    void Dfs_2(int u, int tp) {
        top[u] = tp;
        tree[u] = ++ tim;
        lst[u] = tim;
        if(!son[u]) {rst[u] = tim; return ;}
        Dfs_2(son[u], tp);
        for(int i = head[u]; ~ i; i = G[i].nxt) {
            int v = G[i].v;
            if(v != fa[u] && v != son[u]) Dfs_2(v, v);
        }
        rst[u] = tim;
    }
    
    inline void Sec_G_imp(int x, int y, int w) {
        int tp1 = top[x], tp2 = top[y];
        while(tp1 != tp2) {
            if(deep[tp1] < deep[tp2]) swap(tp1, tp2), swap(x, y);
            Seg_tree.Sec_G(1, n, 1, tree[tp1], tree[x], w);
            x = fa[tp1];
            tp1 = fa[x];
        }
        if(deep[x] < deep[y]) swap(x, y);
        Seg_tree.Sec_G(1, n, 1, tree[y], tree[x], w);
        return ;
    }
    
    int main() {
        n = read();
        for(int i = 0; i < n; i ++) son[i] = -1, head[i] = -1;
        for(int i = 1; i < n; i ++) {int u = read(), v = read(); Add(u, v);}
        Seg_tree.Build_tree(1, n, 1);
        Dfs_1(0, 0, 1);
        Dfs_2(0, 0);
        T = read();
        while(T --) {
            string opt; cin >> opt;
            if(opt[0] == 'A') {
                int x = read(), y = read(), w = read();
                Sec_G_imp(x, y, w);    
            } else {
                Answer = 0;
                int x = read();
                Seg_tree.Sec_A(1, n, 1, lst[x], rst[x]);
                cout << Answer << "
    ";
            }
        }
        
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/shandongs1/p/8968833.html
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