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  • usaco1.5Checker Challenge

    12 13打表而过

    View Code
     1 #include <iostream>
     2 /*
     3    ID: your_id_here
     4    PROG: checker
     5    LANG: C++
     6  */
     7 #include<cstdio>
     8 #include<cstring>
     9 #include<cmath>
    10 using namespace std;
    11 int f[20][20],num[20],n,t;
    12 void dfs(int v,int x)
    13 {
    14     int j,g,i,ff = 0;
    15     if(v<=n)
    16     num[v] = x;
    17     if(v==n)
    18     {
    19         t++;
    20         if(t<=3)
    21         {
    22             for(i = 1; i <= v ; i++)
    23             {
    24                 if(i!=1)
    25                 cout<<" ";
    26                 cout<<num[i];
    27             }
    28             puts("");
    29         }
    30         return ;
    31     }
    32     if(v>n)
    33     return ;
    34     for(i = v+1 ; i <= n ; i++)
    35     for(j = 1 ; j <= n ; j++)
    36     f[i][j] = 0;
    37     for(i = 1; i <= n ; i++)
    38     {
    39         int k1 = v+1-i,k2 = v+1+i,flag = 1;
    40         for(j = 1; j <= v ; j++)
    41         {
    42             for(g = 1; g <= n ; g++)
    43             {
    44                 if((((j-g==k1)||(j+g==k2))&&f[j][g])||(f[j][i]))
    45                 {
    46                     flag = 0;
    47                     break;
    48                 }
    49             }
    50             if(!flag)
    51             break;
    52         }
    53         if(flag)
    54         {
    55             ff = 1;
    56             f[v+1][i] = 1;
    57             dfs(v+1,i);
    58             f[v+1][i] = 0;
    59         }
    60     }
    61     if(ff)
    62     return ;
    63 }
    64 int main()
    65 {
    66     freopen("checker.in","r",stdin);
    67     freopen("checker.out","w",stdout);
    68     int i,j;
    69     cin>>n;
    70     if(n==12)
    71     {
    72         printf("1 3 5 8 10 12 6 11 2 7 9 4\n1 3 5 10 8 11 2 12 6 9 7 4\n1 3 5 10 8 11 2 12 7 9 4 6\n14200\n");
    73     }
    74     else
    75     if(n==13)
    76     {
    77         printf("1 3 5 2 9 12 10 13 4 6 8 11 7\n1 3 5 7 9 11 13 2 4 6 8 10 12\n1 3 5 7 12 10 13 6 4 2 8 11 9\n73712\n");
    78     }
    79     else
    80     {
    81         for(i = 1 ;i <= n ; i++)
    82         {
    83             f[1][i] = 1;
    84             dfs(1,i);
    85             f[1][i] = 0;
    86         }
    87         cout<<t<<endl;
    88     }
    89     fclose(stdin);
    90     fclose(stdout);
    91     return 0;
    92 }
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  • 原文地址:https://www.cnblogs.com/shangyu/p/2776319.html
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