简答题
对于当前点 判断每个点是否可达
1 #include <iostream> 2 #include<cstdio> 3 #include<cstring> 4 #include<algorithm> 5 #include<stdlib.h> 6 #include<vector> 7 #include<queue> 8 #include<string> 9 using namespace std; 10 vector<int>ed[210]; 11 int w[210][210],vis[210]; 12 struct node 13 { 14 char s[35]; 15 int a,b,c; 16 }p[210]; 17 int judge(int x,int y) 18 { 19 int a1 = p[x].a,a2 = p[x].b,a3 = p[x].c; 20 int a4 = p[y].a,a5 = p[y].b,a6 = p[y].c; 21 int o=0; 22 if(a1>a4) 23 o++; 24 if(a2>a5) 25 o++; 26 if(a3>a6) 27 o++; 28 if(o>=2) 29 return 1; 30 return 0; 31 } 32 int spfa(int e,int s) 33 { 34 int i; 35 memset(vis,0,sizeof(vis)); 36 queue<int>q; 37 q.push(s); 38 vis[s] = 1; 39 while(!q.empty()) 40 { 41 int u = q.front(); 42 w[u][s] = 1; 43 q.pop(); 44 for(i = 0 ;i < (int)ed[u].size() ; i++) 45 { 46 int v = ed[u][i]; 47 if(!vis[v]) 48 { 49 vis[v] = 1; 50 q.push(v); 51 } 52 } 53 } 54 if(w[e][s]) 55 return 1; 56 return 0; 57 } 58 int main() 59 { 60 int i,j,n; 61 scanf("%d",&n); 62 for(i = 1; i <= n ; i++) 63 { 64 cin>>p[i].s>>p[i].a>>p[i].b>>p[i].c; 65 } 66 for(i = 1; i <= n ;i++) 67 { 68 for(j = 1; j <= n ; j++) 69 { 70 if(i==j) 71 continue; 72 if(judge(i,j)) 73 { 74 w[i][j] = 1; 75 ed[j].push_back(i); 76 } 77 } 78 } 79 for(i = 1; i <= n ;i++) 80 { 81 int flag = 1; 82 for(j = 1 ; j <= n ;j++) 83 { 84 if(i==j) 85 continue; 86 if(!w[i][j]&&!spfa(i,j)) 87 { 88 flag = 0; 89 break; 90 } 91 } 92 if(flag) 93 printf("%s ",p[i].s); 94 } 95 return 0; 96 }