01 复数的加减乘除操作

#include<stdio.h>
#include<math.h>
struct Complex {
    double a;//实部
    double b;//虚部
};
void initComplex(double x, double y) {
    printf("%.2f+%.2f*i
", x, y);
}
void add(struct Complex complex1, struct Complex complex2) {
    double sumA = complex1.a + complex2.a;
    double sumB = complex1.b + complex2.b;
    printf("两复数的和是：
");
    initComplex(sumA, sumB);
}
void minus(struct Complex complex1, struct Complex complex2) {
    double minusA = complex1.a - complex2.a;
    double minusB = complex1.b - complex2.b;
    printf("两复数的差是：
");
    initComplex(minusA, minusB);
}
void multiply(struct Complex complex1, struct Complex complex2) {
    double mulA = complex1.a * complex2.a - complex1.b * complex2.b;
    double mulB = complex1.b * complex2.a + complex1.a * complex2.b;
    printf("两复数的积是：
");
    initComplex(mulA, mulB);
    //复数乘法公式 z1=a+bi,z2=c+di,z1*z2=(ac-bd)+(bc+ad)i
}
void division(struct Complex complex1, struct Complex complex2) {
    double diviA = (complex1.a * complex2.a + complex1.b * complex2.b) / (pow(complex2.a, 2.0) + pow(complex2.b, 2.0));
    double diviB = (complex1.b * complex2.a - complex1.a * complex2.b) / (pow(complex2.a, 2.0) + pow(complex2.b, 2.0));
    printf("两复数的商是：
");
    initComplex(diviA, diviB);
    //复数乘法公式 z1=a+bi,z2=c+di,z1/z2=(ac+bd)/(c^2+d^2)+( (bc-ad)/(c^2+d^2) )i
}
void main() {
    struct Complex complex1;
    struct Complex complex2;
    //complex1.a = 1;
    //complex1.b = 2;
    printf("请输入第一个复数的实部：
");
    scanf("%lf", &complex1.a);
    printf("请输入第一个复数的虚部:
");
    scanf("%lf", &complex1.b);
    printf("得到第一个复数:");
    initComplex(complex1.a, complex1.b);

    printf("请输入第二个复数的实部：
");
    scanf("%lf", &complex2.a);
    printf("请输入第二个复数的虚部:
");
    scanf("%lf", &complex2.b);
    printf("得到第二个复数:");
    initComplex(complex2.a, complex2.b);

    add(complex1, complex2);
    minus(complex1, complex2);
    multiply(complex1, complex2);
    division(complex1, complex2);
}