记录一次导数据的笔记

保障类型？

联合查询 两个表
select UI.id,UI.notes,SC.id,SC.notes

from renter UI right join house SC on

UI.notes=SC.notes

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联表查询的语句

select UI.id as renterid,UI.notes as renternotes,SC.id as hid,SC.notes as hnotes

from renter UI right join house SC on

UI.notes=SC.notes

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SELECT
UI.id AS renterid,
UI.notes AS renternotes,
SC.id AS hid,
SC.notes AS hnotes
FROM
renter UI
RIGHT JOIN house SC ON UI.notes = SC.notes
WHERE
UI.notes LIKE '%tab2%';
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renterid renternotes hid hnotes

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"月租金":"",
"序号":"序号",

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赵云海

// contract_no:"",
// start_time:1609434000,//2021-01-01 01:00:00
// end_time:0,
// renter_id:"",//luable
// role_a:"乐平市公租房",
// role_b:item["姓名"],//?
// house_id:"",//lable
// house_spec_id:0,
// original_price:item['月租金'],//?
// price:item['月租金'],//?
// cash_money:yj,//? 押金
// policy:"普通",
// status:"正常",
// create_user:0,
// create_time:0,
// update_user:0,
// update_time:0,
// remarks:item.id+"tab1",//额外备注

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contract_20201021012609A1

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http://www.bejson.com/json/col2json/

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承租人的先不改了

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合同的 政策

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房屋的结构 和 ok

安全 级别 全部默认 A

房屋要不要加 状态 比如 火烧? 强占？

保障类型 要不要加进字段里面去 放在房屋 ？

还是把保障类型这个字段放在 合同里面？

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structure='null'

不详

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SELECT DISTINCT(contract_no) from contract

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查询重复的

select contract_no,id from contract
where contract_no in (select contract_no from contract group by contract_no having count(contract_no) > 1);

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1363
1395
32

1392

1395-25

1370

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房屋 474+476+420=1370
承租人 474+476+420=1370
合同 474+476+420=1370

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select contract_no,id from contract where contract_no in (select contract_no from contract group by contract_no having count(contract_no) > 1);

select contract_no,id from contract where contract_no='contract_202010241743095714A1'

select count(*) from contract

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