zoukankan      html  css  js  c++  java
  • 20-语言入门-20-Financial Management

     
    描述
    Larry graduated this year and finally has a job. He's making a lot of money, but somehow never seems to have enough. Larry has decided that he needs to grab hold of his financial portfolio and solve his financing problems. The first step is to figure out what's been going on with his money. Larry has his bank account statements and wants to see how much money he has. Help Larry by writing a program to take his closing balance from each of the past twelve months and calculate his average account balance.

    输入
    The input will be twelve lines. Each line will contain the closing balance of his bank account for a particular month. Each number will be positive and displayed to the penny. No dollar sign will be included.
    输出
    The output will be a single number, the average (mean) of the closing balances for the twelve months. It will be rounded to the nearest penny, preceded immediately by a dollar sign, and followed by the end-of-line. There will be no other spaces or characters in the output.
    样例输入
    100.00
    489.12
    12454.12
    1234.10
    823.05
    109.20
    5.27
    1542.25
    839.18
    83.99
    1295.01
    1.75
    样例输出
    1581.42
     
     
     
    #include <stdio.h>

    const static int CAL_MONTH_COUNT = 12;

    int main()
    {
       
    float result = 0;
       
    float readLen = CAL_MONTH_COUNT;
       
    while (readLen>0)
        {
           
    float currValue = 0;
           
    scanf("%f",&currValue);
           
    getchar();
           
            result += currValue;
           
            --readLen;
        }
       
       
    printf("%.2f ",result/CAL_MONTH_COUNT);
       
       
    return 0;
    }
     
     
    这段英文大差不差的知道大概是求个平均值,对输出结果提出了要求。
     
  • 相关阅读:
    js 宿主对象的属性和方法总结
    java学习路线
    (转)前端学习路线
    第11章 PADS功能使用技巧(2)-最全面
    第11章 PADS功能使用技巧(1)-最全面
    可控硅工作原理及参数详解
    光耦继电器工作原理与参数详解
    EEPROM工作原理透彻详解
    晶振工作原理及参数详解(最透彻)
    逻辑门电路详解1(最透彻)
  • 原文地址:https://www.cnblogs.com/sharpfeng/p/5141737.html
Copyright © 2011-2022 走看看