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  • Python 列表元素分组,比如 [1,2,3,...20]变成 [[1,2,3],[4,5,6]....](列表生成式解决)

    # 生成一个1到20的列表
    a=[x for x in range(1,21)]
    # 把a列表切片,并赋值给b列表,x为0到20且步长为3的列表,在这里具体为[0,3,6,9,12,15,18]
    # 把x带入,b列表为[a[0:0+3],a[3:3+3]……[a[18:18+3]
    b=[a[x:x+3] for x in range(0,20,3)]
    print(a)
    print(b)

    输出为

    [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20]
    [[1, 2, 3], [4, 5, 6], [7, 8, 9], [10, 11, 12], [13, 14, 15], [16, 17, 18], [19, 20]]
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  • 原文地址:https://www.cnblogs.com/shawone/p/10223869.html
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