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  • leetcode 21

    合并两个有序数列。属于基础的数据结构问题,核心在于对链表的操作。

    代码如下:

     1 /**
     2  * Definition for singly-linked list.
     3  * struct ListNode {
     4  *     int val;
     5  *     ListNode *next;
     6  *     ListNode(int x) : val(x), next(NULL) {}
     7  * };
     8  */
     9 class Solution {
    10 public:
    11     ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) {
    12         ListNode* head1 = NULL;
    13         ListNode* head2 = NULL;
    14         ListNode* tmp = NULL;
    15         if(l1 == NULL)
    16         {
    17             return l2;
    18         }
    19         else if(l2 == NULL)
    20         {
    21             return l1;
    22         }
    23         else if(l1->val > l2->val)
    24         {
    25             tmp = l2;
    26             head1 = l1;
    27             head2 = l2->next;
    28         }
    29         else
    30         {
    31             tmp = l1;
    32             head1 = l1->next;
    33             head2 = l2;
    34         }
    35         ListNode* node = tmp;
    36         while(true)
    37         {
    38             if(head1 == NULL)
    39             {
    40                 node->next = head2;
    41                 break;
    42             }
    43             if(head2 == NULL)
    44             {
    45                 node->next = head1;
    46                 break;
    47             }
    48             if(head1->val > head2->val)
    49             {
    50                 node->next = head2;
    51                 head2 = head2->next;
    52             }
    53             else
    54             {
    55                 node->next = head1;
    56                 head1 = head1->next;
    57             }
    58             node = node->next;
    59         }
    60         return tmp;
    61     }
    62 };
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  • 原文地址:https://www.cnblogs.com/shellfishsplace/p/5846134.html
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