zoukankan      html  css  js  c++  java
  • HDU 1022 Train Problem I

    A - Train Problem I
    Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u

    Description

    As the new term comes, the Ignatius Train Station is very busy nowadays. A lot of student want to get back to school by train(because the trains in the Ignatius Train Station is the fastest all over the world ^v^). But here comes a problem, there is only one railway where all the trains stop. So all the trains come in from one side and get out from the other side. For this problem, if train A gets into the railway first, and then train B gets into the railway before train A leaves, train A can't leave until train B leaves. The pictures below figure out the problem. Now the problem for you is, there are at most 9 trains in the station, all the trains has an ID(numbered from 1 to n), the trains get into the railway in an order O1, your task is to determine whether the trains can get out in an order O2. 
     

    Input

    The input contains several test cases. Each test case consists of an integer, the number of trains, and two strings, the order of the trains come in:O1, and the order of the trains leave:O2. The input is terminated by the end of file. More details in the Sample Input. 
     

    Output

    The output contains a string "No." if you can't exchange O2 to O1, or you should output a line contains "Yes.", and then output your way in exchanging the order(you should output "in" for a train getting into the railway, and "out" for a train getting out of the railway). Print a line contains "FINISH" after each test case. More details in the Sample Output. 
     

    Sample Input

    3 123 321 3 123 312
     

    Sample Output

    Yes. in in in out out out FINISH No. FINISH

    Hint

    Hint  For the first Sample Input, we let train 1 get in, then train 2 and train 3.
    So now train 3 is at the top of the railway, so train 3 can leave first, then train 2 and train 1.
    In the second Sample input, we should let train 3 leave first, so we have to let train 1 get in, then train 2 and train 3.
    Now we can let train 3 leave.
    But after that we can't let train 1 leave before train 2, because train 2 is at the top of the railway at the moment.
    So we output "No.".
            
    题意大体是 询问出栈入栈是否符合栈的规定,如果符合 输入顺序;否则no。最后finsh

    代码
     1 #include<cstdio>
     2 #include<cstdlib>
     3 #include<cstring>
     4 #include<algorithm>
     5 #include<vector>
     6 #include<queue>
     7 #include<stack>
     8 #include<set>
     9 #include<iostream>
    10 #include<bits/stdc++.h>
    11 #define ll long long
    12 using namespace std;
    13 int n,i,j,k,flag[20];
    14 char s1[10],s2[10];
    15 int main()
    16 {
    17     stack <char> s;
    18     while(~scanf("%d",&n)){
    19         memset(flag,-1,sizeof(flag));
    20         cin>>s1>>s2;
    21         while(!s.empty()) s.pop();
    22         j=0,k=0;
    23         for(int i=0;i<n;i++){
    24             s.push(s1[i]);
    25             flag[k++]=1;
    26             while(!s.empty()&&s.top()==s2[j])
    27             flag[k++]=0,s.pop(),j++;
    28         }
    29         if(j==n){
    30             printf("Yes.
    ");
    31             for(int i=0;i<k;i++)
    32               if(flag[i]) printf("in
    ");
    33               else printf("out
    ");
    34               printf("FINISH
    ");
    35         }else{
    36             printf("No.
    ");
    37             printf("FINISH
    ");
    38         }    
    39     }
    40     return 0;
    41 }
  • 相关阅读:
    Java多线程之JUC包:ReentrantLock源码学习笔记
    Java多线程之JUC包:Semaphore源码学习笔记
    Java多线程之JUC包:CountDownLatch源码学习笔记
    Java多线程之JUC包:AbstractQueuedSynchronizer(AQS)源码学习笔记
    Java多线程之JUC包:CyclicBarrier源码学习笔记
    架构设计:企业总体架构要如何做?小白也能快速领悟的设计思想
    可参考才是有价值的,架构设计的技改之路从来都不容易
    架构设计:高并发读取,高并发写入,并发设计规划落地方案思考
    微服务手册:API接口9个生命节点,构建全生命周期管理
    百度api使用心得体会
  • 原文地址:https://www.cnblogs.com/shenben/p/5459858.html
Copyright © 2011-2022 走看看