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  • AtCoder Beginner Contest 044 A

    Time limit : 2sec / Memory limit : 256MB

    Score : 100 points

    Problem Statement

    There is a hotel with the following accommodation fee:

    • X yen (the currency of Japan) per night, for the first K nights
    • Y yen per night, for the (K+1)-th and subsequent nights

    Tak is staying at this hotel for N consecutive nights. Find his total accommodation fee.

    Constraints

    • 1≤N,K≤10000
    • 1≤Y<X≤10000
    • N, K, X, Y are integers.

    Input

    The input is given from Standard Input in the following format:

    N
    K
    X
    Y
    

    Output

    Print Tak's total accommodation fee.


    Sample Input 1

    Copy
    5
    3
    10000
    9000
    

    Sample Output 1

    Copy
    48000
    

    The accommodation fee is as follows:

    • 10000 yen for the 1-st night
    • 10000 yen for the 2-nd night
    • 10000 yen for the 3-rd night
    • 9000 yen for the 4-th night
    • 9000 yen for the 5-th night

    Thus, the total is 48000 yen.


    Sample Input 2

    Copy
    2
    3
    10000
    9000
    

    Sample Output 2

    Copy
    20000

    题解:水过
     1 #include <iostream>
     2 #include <algorithm>
     3 #include <cstring>
     4 #include <cstdio>
     5 #include <vector>
     6 #include <cstdlib>
     7 #include <iomanip>
     8 #include <cmath>
     9 #include <ctime>
    10 #include <map>
    11 #include <set>
    12 #include <queue>
    13 #include <stack>
    14 using namespace std;
    15 #define lowbit(x) (x&(-x))
    16 #define max(x,y) (x>y?x:y)
    17 #define min(x,y) (x<y?x:y)
    18 #define MAX 100000000000000000
    19 #define MOD 1000000007
    20 #define pi acos(-1.0)
    21 #define ei exp(1)
    22 #define PI 3.141592653589793238462
    23 #define INF 0x3f3f3f3f3f
    24 #define mem(a) (memset(a,0,sizeof(a)))
    25 typedef long long ll;
    26 ll gcd(ll a,ll b){
    27     return b?gcd(b,a%b):a;
    28 }
    29 bool cmp(int x,int y)
    30 {
    31     return x>y;
    32 }
    33 const int N=10005;
    34 const int mod=1e9+7;
    35 int main()
    36 {
    37     std::ios::sync_with_stdio(false);
    38     int n,k,x,y;
    39     cin>>n>>k>>x>>y;
    40     ll s=0;
    41     if(n<=k) s+=n*x;
    42     else s+=k*x+(n-k)*y;
    43     cout<<s<<endl;
    44     return 0;
    45 }
    View Code
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  • 原文地址:https://www.cnblogs.com/shixinzei/p/7288482.html
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