hdu 1263 水果(map)

题目链接：https://vjudge.net/problem/HDU-1263

　　map嵌套就行了

#include<set>
#include<map>
#include<stack>
#include<queue>
#include<cmath>
#include<cstdio>
#include<cctype>
#include<string>
#include<vector>
#include<climits>
#include<cstring>
#include<cstdlib>
#include<iostream>
#include<algorithm>
#define max(a, b) (a > b ? a : b)
#define min(a, b) (a < b ? a : b)
#define mst(a) memset(a, 0, sizeof(a)*maxn)
#define _test printf("~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\n")
using namespace std;
typedef long long ll;
typedef pair<int, int> P;
const double eps = 1e-7;
const int INF = 0x3f3f3f3f;
const ll ll_INF = 233333333333333;
string plc;
int main(void) {
    //std::ios::sync_with_stdio(false);
    map<string, map<string, int> > a; 
    //先定义一个水果名字->水果数量的映射，再定义一个产地->水果信息的映射
    int t;
    scanf("%d", &t);
    while(t--) {
        int n;
        scanf("%d", &n);
        string place, fruname;
        int cnt;
        for (int i = 0; i<n; ++i) {
            cin >> fruname >> place >> cnt;
            a[place][fruname] += cnt; //双重映射的一种访问方式
        }
        map<string, map<string, int> >::iterator it;
        for (it = a.begin(); it != a.end(); ++it) {
            cout << it->first << endl;
            map<string, int>::iterator it2;
            for (it2 = it->second.begin(); it2 != it->second.end(); ++it2)
                cout << "   |----" << it2->first << '(' << it2->second << ')' << endl;
        }
        a.clear();
        if (t)
            cout << endl;
    }
    return 0;
}