zoukankan      html  css  js  c++  java
  • uva-10382-贪心

      题意:对于长为L,宽为W的矩形草地,需要对它进行浇水,总共有n个水龙头,给每个水龙头的浇水半径,和位置.求覆盖整个草地需要的最小水龙头数量.

    如图,把浇水的面积转换成矩形,然后就和区间覆盖一样了,直接贪心

    WA了很多次, w/2 >= r这里,w一直用整数,一直wa

    #include"pch.h"
    #include <string>
    #include<iostream>
    #include<map>
    #include<memory.h>
    #include<vector>
    #include<algorithm>
    #include<queue>
    #include<vector>
    #include<stack>
    #include<math.h>
    #include<iomanip>
    #include<bitset>
    #include"math.h"
    namespace cc
    {
        using std::cout;
        using std::endl;
        using std::cin;
        using std::map;
        using std::vector;
        using std::string;
        using std::sort;
        using std::priority_queue;
        using std::greater;
        using std::vector;
        using std::swap;
        using std::stack;
        using std::bitset;
    
    
    
        class Input
        {
        public:
            double s = 0;
            double e = 0;
        };
    
        constexpr int N = 10010;
    
        int n, l, w;
        Input ins[N];
    
        int min = 0;
    
    
    
        bool cmp(const Input& in1, const Input& in2)
        {
            return in1.s <  in2.s;
        }
    
        int flag = 0;
        void search()
        {
            double curL = 0;
            double curR = 0;
            for (int i = 0;i < n; )
            {
                int j = i;
                while (j < n && ins[j].s <= curL)
                {
                    if (ins[j].e >= curR)
                        curR = ins[j].e;
                    ++j;
                }
                if (i == j)
                    break;
                i = j;
                curL = curR;
                ++min;
                if (curL >= l)
                {
                    flag = 1;
                    break;
                }
    
            }
    
        }
    
        void solve()
        {
            while (cin >> n >> l >> w)
            {
                double p, r;
                min = 0;
    
                flag = 0;
                int total = 0;
                int isok = 0;
                for (int i = 0;i < n;i++)
                {
                    cin >> p >> r;
                    if (w*1.0 / 2 >= r)
                        continue;
                    double x = sqrt((r*r - (w*w*0.25)));
                    Input in;
                    in.s = p - x;
                    in.e = p + x;
                    if (in.s < 0)
                        in.s = 0;
                    ins[total++] = in;
                    if (in.e >= l)
                        isok = 1;
                }
                if (!isok)
                {
                    cout << "-1" << endl;
                    continue;
                }
    
                n = total;
                sort(ins, ins + n, cmp);
                search();
                if (flag == 0)
                    cout << -1 << endl;
                else
                    cout << min << endl;
            }
        }
    
    };
    
    
    int main()
    {
    
    #ifndef ONLINE_JUDGE
        freopen("d://1.text", "r", stdin);
    #endif // !ONLINE_JUDGE
        cc::solve();
    
        return 0;
    }
  • 相关阅读:
    android 网络 post get
    java 命名规范
    android 判断service是否开启
    android 无线连接eclipse
    eclipse jar java.lang.NoClassDefFoundError
    eclipse 默认 utf8
    timer timetask handler
    android 自定义动画按钮
    设计网站
    java 分解arraylist中单个对象 的属性名与值
  • 原文地址:https://www.cnblogs.com/shuiyonglewodezzzzz/p/10289670.html
Copyright © 2011-2022 走看看