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  • 【NOI2018】归程

    题面

    https://www.luogu.org/problem/P4768

    题解

    #include<cstdio>
    #include<iostream>
    #include<vector>
    #include<queue>
    #include<cstring>
    #include<algorithm>
    using namespace std;
    
    int dis[205000];
    bool vis[205000];
    
    inline int read() {
      int x=0,f=1;char c=getchar();
      while(c<'0'||c>'9'){if(c=='-')f=-1;c=getchar();}
      while(c>='0'&&c<='9'){x=x*10+c-'0';c=getchar();}
      return x*f;
    }
    
    struct node {
      int lb,rb,lson,rson,fa,mindis,dep;
    } tree[20000500];
    
    struct edge {
      int u,v,l,h;
      bool operator < (const edge rhs) const {
        return h<rhs.h;
      }
    } a[405000];
    
    struct node2 {
      int u,d;
      bool operator < (const node2 rhs) const {
        return d>rhs.d;
      }
    };
    
    vector<int> to[205000],len[205000];
    
    int n,m,cnt,root[405000];
    
    void dij() {
      register int i;
      priority_queue<node2> pq;
      while (!pq.empty()) pq.pop();
      dis[1]=0;
      for (i=2;i<=n;i++) dis[i]=2e9+5;
      memset(vis,0,sizeof(vis));
      pq.push((node2){1,0});
      while (!pq.empty()) {
        node2 x=pq.top(); pq.pop();
        if (vis[x.u]) continue;
        dis[x.u]=x.d;
        vis[x.u]=true;
        for (i=to[x.u].size()-1;i>=0;i--) if (x.d+len[x.u][i]<dis[to[x.u][i]]) {
          dis[to[x.u][i]]=x.d+len[x.u][i];
          pq.push((node2){to[x.u][i],dis[to[x.u][i]]});
        }
      }
    }
    
    void maketree(register int now,register int l,register int r){
      tree[now].lb=l; tree[now].rb=r;
      if (l==r) {
        tree[now].fa=l;
        tree[now].mindis=dis[l];
        tree[now].dep=1;
        return;
      }
      // fa to a loc
      register int mid=(l+r)/2;
      tree[now].lson=cnt+1;
      maketree(++cnt,l,mid);
      tree[now].rson=cnt+1;
      maketree(++cnt,mid+1,r);
    }
    
    void build(register int now,register int old,register int uu,register int vv) {
      tree[now]=tree[old];
      register int l=tree[now].lb,r=tree[now].rb,mid=(l+r)/2;
      if (l==r) return;
      if ((l<=uu&&uu<=mid)||(l<=vv&&vv<=mid)) 
        tree[now].lson=cnt+1,build(++cnt,tree[old].lson,uu,vv);
      if ((mid+1<=uu&&uu<=r)||(mid+1<=vv&&vv<=r))
        tree[now].rson=cnt+1,build(++cnt,tree[old].rson,uu,vv);
    }
    
    int find(register int now,register int loc) { //return a poregister int
      if (tree[now].lb==tree[now].rb) return now;
      if (loc<=(tree[now].lb+tree[now].rb)/2) 
      return find(tree[now].lson,loc);
      else return find(tree[now].rson,loc);
    }
    
    int findroot(register int now,register int cur) { //return a loc
      if (tree[now].fa==tree[now].lb) return tree[now].lb; 
        else return findroot(find(root[cur],tree[now].fa),cur);
    }
    
    void kru(){
      register int i,j,uu,vv;
      sort(a+1,a+m+1);
      cnt=0;
      root[m+1]=1;
      maketree(++cnt,1,n);
      for (i=m;i>=1;i--) {
        uu=findroot(find(root[i+1],a[i].u),i+1);
        vv=findroot(find(root[i+1],a[i].v),i+1);
        if (uu==vv) {
          root[i]=root[i+1];
          continue;
        }
        root[i]=cnt+1;
        build(++cnt,root[i+1],uu,vv);
        uu=find(root[i],uu);
        vv=find(root[i],vv);
    
        if (tree[uu].dep<tree[vv].dep) {
          tree[vv].dep=max(tree[vv].dep,tree[uu].dep+1);
          tree[vv].mindis=min(tree[vv].mindis,tree[uu].mindis);
          tree[uu].fa=tree[vv].lb;
        }
        else {
        tree[uu].dep=max(tree[uu].dep,tree[vv].dep+1);
          tree[uu].mindis=min(tree[uu].mindis,tree[vv].mindis);
          tree[vv].fa=tree[uu].lb;
        }
      }
    }
    
    int main(){
      register int T,i,j,v,q,k,s,p,lastans;
      T=read();
      while (T--) {
        n=read(); m=read();
        for (i=1;i<=n;i++) to[i].clear(),len[i].clear();
        for (i=1;i<=m;i++) {
        a[i].u=read(); a[i].v=read(); a[i].l=read(); a[i].h=read();
          to[a[i].u].push_back(a[i].v); len[a[i].u].push_back(a[i].l);
          to[a[i].v].push_back(a[i].u); len[a[i].v].push_back(a[i].l);
        }
        dij();
        kru();
        q=read(); k=read(); s=read();
        lastans=0;
        a[m+1].h=2e9+5;
        for (i=1;i<=q;i++) {
          v=read(); p=read();
          v=(v+k*lastans-1)%n+1;
          p=(p+k*lastans)%(s+1);
          register int cur=upper_bound(a+1,a+m+2,(edge){0,0,0,p})-a;
          register int ans=find(root[cur],findroot(find(root[cur],v),cur));
          printf("%d
    ",tree[ans].mindis);
          lastans=tree[ans].mindis;
        }
      }
    }
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  • 原文地址:https://www.cnblogs.com/shxnb666/p/11275457.html
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