zoukankan      html  css  js  c++  java
  • 10、有效的数独

    10、有效的数独

    判断一个 9x9 的数独是否有效。只需要根据以下规则,验证已经填入的数字是否有效即可。

    1. 数字 1-9 在每一行只能出现一次。
    2. 数字 1-9 在每一列只能出现一次。
    3. 数字 1-9 在每一个以粗实线分隔的 3x3 宫内只能出现一次。

    上图是一个部分填充的有效的数独。

    数独部分空格内已填入了数字,空白格用 '.' 表示。

    示例 1:

    输入:
    [
      ["5","3",".",".","7",".",".",".","."],
      ["6",".",".","1","9","5",".",".","."],
      [".","9","8",".",".",".",".","6","."],
      ["8",".",".",".","6",".",".",".","3"],
      ["4",".",".","8",".","3",".",".","1"],
      ["7",".",".",".","2",".",".",".","6"],
      [".","6",".",".",".",".","2","8","."],
      [".",".",".","4","1","9",".",".","5"],
      [".",".",".",".","8",".",".","7","9"]
    ]
    输出: true
    

    示例 2:

    输入:
    [
      ["8","3",".",".","7",".",".",".","."],
      ["6",".",".","1","9","5",".",".","."],
      [".","9","8",".",".",".",".","6","."],
      ["8",".",".",".","6",".",".",".","3"],
      ["4",".",".","8",".","3",".",".","1"],
      ["7",".",".",".","2",".",".",".","6"],
      [".","6",".",".",".",".","2","8","."],
      [".",".",".","4","1","9",".",".","5"],
      [".",".",".",".","8",".",".","7","9"]
    ]
    输出: false
    解释: 除了第一行的第一个数字从 5 改为 8 以外,空格内其他数字均与 示例1 相同。
         但由于位于左上角的 3x3 宫内有两个 8 存在, 因此这个数独是无效的。
    

    说明:

    • 一个有效的数独(部分已被填充)不一定是可解的。
    • 只需要根据以上规则,验证已经填入的数字是否有效即可。
    • 给定数独序列只包含数字 1-9 和字符 '.'
    • 给定数独永远是 9x9 形式的。

    答案解析:

    import java.util.*;
    class Solution {
        public boolean isValidSudoku(char[][] board) {
            int row = board.length;//横着的行
            int col = board[0].length;//竖着的列
    
            if (row != 9||col != 9){
                return false;
            }
            Map<Character,Boolean> map = new HashMap<>();//键为1-9,值为true或者false
            //检查row
            for (int i = 0; i < row; i++) {
                map.clear();
                for (int j = 0; j < col; j++) {
                    char cur = board[i][j];
                    if (cur != '.'){
                        if (map.containsKey(cur)){
                            return false;
                        }else {
                            map.put(cur, true);
                        }
                    }
                }
            }
    
            //检查col
            for (int i = 0; i < col; i++) {
                map.clear();
                for (int j = 0; j < row; j++) {
                    char cur = board[j][i];
                    if (cur != '.'){
                        if (map.containsKey(cur)){
                            return false;
                        }else {
                            map.put(cur, true);
                        }
                    }
                }
            }
            //检查9宫格
            //1,2,3
            //4,5,6
            //7,8,9
            for (int i = 0; i < 9; i++) {
                int rowBegin = (i%3)*3;//行开始
                int colBegin = i - rowBegin/3;//列开始
                map.clear();
                for (int j = rowBegin; j < rowBegin + 3; j++) {
                    for (int k = colBegin; k < colBegin + 3; k++) {
                        char cur = board[j][k];
                        if (cur != '.'){
                            if (map.containsKey(cur)){
                                return false;
                            }else {
                                map.put(cur, true);
                            }
                        }
                    }
                }
            }
            return true;
        }
    }
    
  • 相关阅读:
    2020年勒索软件攻击最多的四大漏洞
    物联网时代,我们还能有哪些隐私?
    区块链技术最重要价值所在
    为什么云遣返不仅仅是从公共云回到内部部署环境
    如何应对越来越多的物联网勒索软件威胁?
    如何将边缘计算与核心系统集成
    莫唱衰:5G开局很快,但原力呈现才刚刚开始
    云原生架构支撑千万级DAU游戏
    变革型AI、无代码与低代码——哪一种才是企业AI部署的理想途径?
    nginx代理的配置和文件访问权限配置
  • 原文地址:https://www.cnblogs.com/sikaozhifu/p/10752905.html
Copyright © 2011-2022 走看看