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  • 599. Minimum Index Sum of Two Lists(easy)

    Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings.

    You need to help them find out their common interest with the least list index sum. If there is a choice tie between answers, output all of them with no order requirement. You could assume there always exists an answer.

    Example 1:

    Input:
    ["Shogun", "Tapioca Express", "Burger King", "KFC"]
    ["Piatti", "The Grill at Torrey Pines", "Hungry Hunter Steakhouse", "Shogun"]
    Output: ["Shogun"]
    Explanation: The only restaurant they both like is "Shogun".
    

    Example 2:

    Input:
    ["Shogun", "Tapioca Express", "Burger King", "KFC"]
    ["KFC", "Shogun", "Burger King"]
    Output: ["Shogun"]
    Explanation: The restaurant they both like and have the least index sum is "Shogun" with index sum 1 (0+1).
    

    Note:

    1. The length of both lists will be in the range of [1, 1000].
    2. The length of strings in both lists will be in the range of [1, 30].
    3. The index is starting from 0 to the list length minus 1.
    4. No duplicates in both lists.
    /*
    暴力的话O(n^2),可以利用hashtable,用空间来换时间。
    */
    class Solution {
    public:
        vector<string> findRestaurant(vector<string>& list1, vector<string>& list2) {
            vector<string> res;
            map<string, int> data;
            int minval = INT_MAX;
            for (int i = 0; i < list1.size(); i++){   // 存入hashtable中
                data.insert(pair<string, int>(list1[i], i));
            }
            for (int i = 0; i < list2.size(); i++){
                if (data.find(list2[i]) != data.end()){
                   if (data[list2[i]] + i < minval){
                       minval = data[list2[i]] + i;
                       res.clear();
                       res.push_back(list2[i]);
                   }else if (data[list2[i]] + i == minval){
                       res.push_back(list2[i]);
                   }
                }
            }
            return res;
        }
    };
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  • 原文地址:https://www.cnblogs.com/simplepaul/p/7838690.html
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