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  • 洛谷 P3386 【模板】二分图最大匹配

    传送门

    #include <bits/stdc++.h>
    
    using namespace std;
    using ll = long long;
    using p = pair<int, int>;
    const double pi(acos(-1));
    const int inf(0x3f3f3f3f);
    const int mod(1e9 + 7);
    const int maxn(1e3 + 10);
    const int maxm(1e5 + 10);
    int ecnt, head[maxn];
    bool vis[maxn];
    int match[maxn];
    
    struct edge {
        int to, nxt;
    } edges[maxm];
    
    template<typename T = int>
    inline const T read()
    {
        T x = 0, f = 1;
        char ch = getchar();
        while (ch < '0' || ch > '9') {
            if (ch == '-') f = -1;
            ch = getchar();
        }
        while (ch >= '0' && ch <= '9') {
            x = (x << 3) + (x << 1) + ch - '0';
            ch = getchar();
        }
        return x * f;
    }
    
    template<typename T>
    inline void write(T x, bool ln)
    {
        if (x < 0) {
            putchar('-');
            x = -x;
        }
        if (x > 9) write(x / 10, false);
        putchar(x % 10 + '0');
        if (ln) putchar(10);
    }
    
    void addEdge(int u, int v)
    {
        edges[ecnt].to = v;
        edges[ecnt].nxt = head[u];
        head[u] = ecnt++;
    }
    
    bool dfs(int u)
    {
        for (int i = head[u]; compl i; i = edges[i].nxt) {
            int v = edges[i].to;
            if (not vis[v]) {
                vis[v] = true;
                if (not match[v] or dfs(match[v])) {
                    match[v] = u;
                    return true;
                }
            }
        }
        return false;
    }
    
    int hungary(int n)
    {
        int res = 0;
        for (int i = 1; i <= n; ++i) {
            memset(vis, false, sizeof vis);
            res += dfs(i);
        }
        return res;
    }
    
    int main()
    {
    #ifdef ONLINE_JUDGE
    #else
        freopen("input.txt", "r", stdin);
    #endif
        ios::sync_with_stdio(false);
        memset(head, -1, sizeof head);
        int n = read(), m = read(), e = read();
        while (e--) {
            int u = read(), v = read() + n;
            addEdge(u, v);
            addEdge(v, u);
        }
        write(hungary(n), true);
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/singularity2u/p/13934055.html
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