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  • 三天打鱼两天晒网

    /*
    Date: 11/03/19 11:04
    Description: 三天打鱼两天晒网
    */
    #include<stdio.h>

    int sumDate(int year,int month,int day);
    bool judge(int sumday);
    bool leap(int year);

    int main(void)
    {
      int year,month,day,sumday;
      bool flag;

      printf("请输入今天的日期: ");
      scanf("%d%d%d",&year,&month,&day);
      sumday=sumDate(year,month,day);
      flag=judge(sumday);
      if(flag==true)
        printf("%d-%d-%d,今天该打鱼!",year,month,day);
      else
        printf("%d-%d-%d,今天该晒网!",year,month,day);

      return 0;
    }
    bool leap(int year)//该函数用于判断是否为闰年
    {
      bool lep=false;
      if(year%4==0&&year%100!=0||year%400==0)//判断闰年
        lep=true;
      return lep;
    }
    int sumDate(int year,int month,int day)//该函数用于求总天数
    {
      int year1=1990,month1=1,day1=1;//起始年-月-日
      int count=0;//统计该年以前闰年年份数
      int passday=0;//过去年份的总天数
      int nowday=0;//当前年份的总天数
      int sumday=0;//统计总天数
      int mon[]={31,28,31,30,31,30,31,31,30,31,30,31};//每月对应的天数

      for(year1;year1<year;year1++)
      {
        passday+=365;//每一年先按照365天算
        if(leap(year1)==true)
          count++;//是闰年count+1
      }
      passday=passday+count;
      printf("前面年份的天数=%d ",passday);

      for(int i=0;i<month-1;i++)
        nowday+=mon[i];
      nowday=nowday+day;
      if(leap(year)==true&&month>=3)
      {
        nowday+=1;
      }
      printf("今年的天数=%d ",nowday);
      sumday=passday+nowday;
      printf("总天数=%d ",sumday);
      return sumday;
    }
    bool judge(int sumday)//该函数用于判断打鱼还是晒网
    {
      bool flag;
      switch(sumday%5)
      {
        case 1://1、2、3天打鱼flag置为true
        case 2:
        case 3:
          flag=true; break;
        case 0://4、5天晒网flag置为false
        case 4:
          flag=false; break;
        default: break;
      }
      return flag;
    }

    【运行结果】

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  • 原文地址:https://www.cnblogs.com/sinlearn/p/10510083.html
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