public class Kruskal { public static void main(String[] args) { //二维数组 分别存储边的起点 终点 和权值 int [][]edges = {{0,1,6},{0,2,1},{0,3,5},{1,2,5},{1,4,3},{2,3,5},{2,4,6},{2,5,4},{3,5,2},{4,5,6}}; int []connect = {0,1,2,3,4,5};//辅助数组 用来存储两个顶点是否连通 初始都不连通 quick_sort(edges,0,edges.length-1);//对边进行排序 for(int i=0;i<edges.length;i++){ int v1 = edges[i][0]; //边的起点 int v2 = edges[i][1]; //边的终点 int vc1 = connect[v1]; //起点的连通状态 int vc2 = connect[v2]; //终点的连通状态 if(vc1 != vc2){ //如果两个点不连通 则将其加入到最小生成树 并将连通状态改为相同的状态 System.out.println((v1+1)+"->"+(v2+1)); for(int j=0;j<connect.length;j++){ if(connect[j] == vc2) connect[j] = vc1; } } } } public static void quick_sort(int a[][],int low,int high){ if(low < high){ int k = sort(a,low,high); quick_sort(a,low,k-1); quick_sort(a,k+1,high); } } public static int sort(int a[][],int low,int high){ int[] k = a[low]; while(low<high){ while(low <high && k[2] <= a[high][2]) high--; a[low] = a[high]; while(low <high && k[2] >= a[low][2]) low++; a[high] = a[low]; } a[low] = k; return low; } }