zoukankan      html  css  js  c++  java
  • [结题报告]10082 WERTYU Time limit: 3.000 seconds

    Problem C: WERTYU

    A common typing error is to place the hands on the keyboard one row to the right of the correct position. So "Q" is typed as "W" and "J" is typed as "K" and so on. You are to decode a message typed in this manner.

    Input consists of several lines of text. Each line may contain digits, spaces, upper case letters (except Q, A, Z), or punctuation shown above [except back-quote (`)]. Keys labelled with words [Tab, BackSp, Control,etc.] are not represented in the input. You are to replace each letter or punction symbol by the one immediately to its left on the QWERTY keyboard shown above. Spaces in the input should be echoed in the output.

    Sample Input

    O S, GOMR YPFSU/
    

    Output for Sample Input

    I AM FINE TODAY.

    参考代码:
    把字符换成键盘的左边一个字符(最左边的,回车的控制键无效),不多说,上代码..
    #include<stdio.h>
     int main()
     {
         char a;
         while(scanf("%c",&a)!=EOF)
         {if(a=='=') printf("-");
          else if(a=='-')printf("0");
          else if(a=='0')printf("9");
          else if(a=='9')printf("8");
          else if(a=='8')printf("7");
          else if(a=='7')printf("6");
          else if(a=='6')printf("5");
          else if(a=='5')printf("4");
          else if(a=='4')printf("3");
          else if(a=='3')printf("2");
          else if(a=='2')printf("1");
          else if(a=='1')printf("`");
          else if(a=='\\')printf("]");
          else if(a==']')printf("[");
          else if(a=='[')printf("P");
          else if(a=='P')printf("O");
          else if(a=='O')printf("I");
          else if(a=='I')printf("U");
          else if(a=='U')printf("Y");
          else if(a=='Y')printf("T");
          else if(a=='T')printf("R");
          else if(a=='R')printf("E");
          else if(a=='E')printf("W");
          else if(a=='W')printf("Q");
          else if(a=='\'')printf(";");
          else if(a==';')printf("L");
          else if(a=='L')printf("K");
          else if(a=='K')printf("J");
          else if(a=='J')printf("H");
          else if(a=='H')printf("G");
          else if(a=='G')printf("F");
          else if(a=='F')printf("D");
          else if(a=='D')printf("S");
          else if(a=='S')printf("A");
          else if(a=='/')printf(".");
          else if(a=='.')printf(",");
          else if(a==',')printf("M");
          else if(a=='M')printf("N");
          else if(a=='N')printf("B");
          else if(a=='B')printf("V");
          else if(a=='V')printf("C");
          else if(a=='C')printf("X");
          else if(a=='X')printf("Z");
          else printf("%c",a);
         }
             return 0;
     }
  • 相关阅读:
    详解并发和并行意义
    MoleHill Getting Started AGAL(转)
    解决setInterval计时器不准的问题
    Flash视频播放器开发经验总结
    利用pushState开发无刷页面切换
    用小乐图客抓取人人网照片
    如何在Flash中新窗口打开页面而不被拦截
    响应式开发总结
    用Asroute解决复杂状态切换问题
    对iframe跨域通信的封装
  • 原文地址:https://www.cnblogs.com/sjy123/p/2919972.html
Copyright © 2011-2022 走看看