将数字金额转换成大写人民币形式（网站收到的一个方法很不错）

 /**////   <summary>    
        ///   将数字金额转换成大写人民币形式。  
        ///   </summary>    
        ///   <param   name="num">金额</param>    
        ///   <returns>返回大写形式</returns>    
        public static string CmycurD(decimal num)
        {
            string str1 = "零壹贰叁肆伍陆柒捌玖";                         //0-9所对应的汉字    
            string str2 = "万仟佰拾亿仟佰拾万仟佰拾元角分";   //数字位所对应的汉字    
            string str3 = "";         //从原num值中取出的值    
            string str4 = "";         //数字的字符串形式    
            string str5 = "";     //人民币大写金额形式    
            int i;         //循环变量    
            int j;         //num的值乘以100的字符串长度    
            string ch1 = "";         //数字的汉语读法    
            string ch2 = "";         //数字位的汉字读法    
            int nzero = 0;     //用来计算连续的零值是几个    
            int temp;                         //从原num值中取出的值    

            num = Math.Round(Math.Abs(num), 2);         //将num取绝对值并四舍五入取2位小数    
            str4 = ((long)(num * 100)).ToString();                 //将num乘100并转换成字符串形式    
            j = str4.Length;             //找出最高位    
            if (j > 15) { return "溢出"; }
            str2 = str2.Substring(15 - j);       //取出对应位数的str2的值。如：200.55,j为5所以str2=佰拾元角分    

            //循环取出每一位需要转换的值    
            for (i = 0; i < j; i++)
            {
                str3 = str4.Substring(i, 1);                     //取出需转换的某一位的值    
                temp = Convert.ToInt32(str3);             //转换为数字    
                if (i != (j - 3) && i != (j - 7) && i != (j - 11) && i != (j - 15))
                {
                    //当所取位数不为元、万、亿、万亿上的数字时    
                    if (str3 == "0")
                    {
                        ch1 = "";
                        ch2 = "";
                        nzero = nzero + 1;
                    }
                    else
                    {
                        if (str3 != "0" && nzero != 0)
                        {
                            ch1 = "零" + str1.Substring(temp * 1, 1);
                            ch2 = str2.Substring(i, 1);
                            nzero = 0;
                        }
                        else
                        {
                            ch1 = str1.Substring(temp * 1, 1);
                            ch2 = str2.Substring(i, 1);
                            nzero = 0;
                        }
                    }
                }
                else
                {
                    //该位是万亿，亿，万，元位等关键位    
                    if (str3 != "0" && nzero != 0)
                    {
                        ch1 = "零" + str1.Substring(temp * 1, 1);
                        ch2 = str2.Substring(i, 1);
                        nzero = 0;
                    }
                    else
                    {
                        if (str3 != "0" && nzero == 0)
                        {
                            ch1 = str1.Substring(temp * 1, 1);
                            ch2 = str2.Substring(i, 1);
                            nzero = 0;
                        }
                        else
                        {
                            if (str3 == "0" && nzero >= 3)
                            {
                                ch1 = "";
                                ch2 = "";
                                nzero = nzero + 1;
                            }
                            else
                            {
                                if (j >= 11)
                                {
                                    ch1 = "";
                                    nzero = nzero + 1;
                                }
                                else
                                {
                                    ch1 = "";
                                    ch2 = str2.Substring(i, 1);
                                    nzero = nzero + 1;
                                }
                            }
                        }
                    }
                }
                if (i == (j - 11) || i == (j - 3))
                {
                    //如果该位是亿位或元位，则必须写上    
                    ch2 = str2.Substring(i, 1);
                }
                str5 = str5 + ch1 + ch2;

                if (i == j - 1 && str3 == "0")
                {
                    //最后一位（分）为0时，加上“整”    
                    str5 = str5 + '整';
                }
            }
            if (num == 0)
            {
                str5 = "零元整";
            }
            return str5;
        }