题目描述:(链接)
Given a sorted linked list, delete all duplicates such that each element appear only once.
For example,
Given 1->1->2
, return 1->2
.
Given 1->1->2->3->3
, return 1->2->3
.
解题思路:
1 /** 2 * Definition for singly-linked list. 3 * struct ListNode { 4 * int val; 5 * ListNode *next; 6 * ListNode(int x) : val(x), next(NULL) {} 7 * }; 8 */ 9 class Solution { 10 public: 11 ListNode* deleteDuplicates(ListNode* head) { 12 ListNode *prev = NULL; 13 for (ListNode *cur = head; cur != NULL; cur = cur->next) { 14 if (cur == head) { 15 prev = cur; 16 continue; 17 } 18 19 if (cur->val == prev->val) { 20 prev->next = cur->next; 21 } else { 22 prev = cur; 23 } 24 } 25 26 return head; 27 } 28 };
递归版:2015-10-26更新
1 /** 2 * Definition for singly-linked list. 3 * struct ListNode { 4 * int val; 5 * ListNode *next; 6 * ListNode(int x) : val(x), next(NULL) {} 7 * }; 8 */ 9 class Solution { 10 public: 11 ListNode* deleteDuplicates(ListNode* head) { 12 if (!head || !(head->next)) return head; 13 14 ListNode *p = head->next; 15 if (p->val == head->val) { 16 while (p && p->val == head->val) { 17 ListNode *tmp = p; 18 p = p->next; 19 delete tmp; 20 } 21 head->next = p; 22 return deleteDuplicates(head); 23 } else { 24 head->next = deleteDuplicates(p); 25 return head; 26 } 27 } 28 };