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  • hdu 3400 line belt (三分搜索)

    #include<stdio.h>
    #include<math.h>
    #define eps 0.00000001
    struct node
    {
        double x,y;
    }a,b,c,d;
    double p,q,r;
    void init()
    {
        scanf("%lf%lf%lf%lf",&a.x,&a.y,&b.x,&b.y);
        scanf("%lf%lf%lf%lf",&c.x,&c.y,&d.x,&d.y);
        scanf("%lf%lf%lf",&p,&q,&r);
    }
    double dist(node a,node b)
    {
        return sqrt((a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y));
    }
    double scd(node p1,double m)
    {
        node p2;
        p2.x=c.x+(d.x-c.x)*m;
        p2.y=c.y+(d.y-c.y)*m;
        return dist(p1,p2)/r+dist(d,p2)/q;
    }
    double solvecd(node p1)
    {
        double l=0.0,r=1.0,mid,mmid,ans1,ans2;
        while(l+eps<r)
        {
            mid=(l+r)/2;
            mmid=(mid+r)/2;
            ans1=scd(p1,mid);
            ans2=scd(p1,mmid);
            if(ans1<ans2) r=mmid;
            else l=mid;
        }
        return scd(p1,l);
    }
    double sab(double m)
    {
        node p1;
        p1.x=a.x+(b.x-a.x)*m;
        p1.y=a.y+(b.y-a.y)*m;
        return dist(a,p1)/p+solvecd(p1);
    }
    double solveab()
    {
        double l=0.0,r=1.0,mid,mmid,ans1,ans2;
        while(l+eps<r)
        {
            mid=(l+r)/2;
            mmid=(mid+r)/2;
            ans1=sab(mid);
            ans2=sab(mmid);
            if(ans1<ans2) r=mmid;
            else l=mid;
        }
        return sab(l);
    }
    int main()
    {
        int cs;scanf("%d",&cs);
        while(cs--)
        {
          init();
          double ans=solveab();
          printf("%.2f\n",ans);
        }
        return 0;
    }
    Just a little, maybe change the world
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  • 原文地址:https://www.cnblogs.com/skyming/p/2486678.html
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