题目链接
https://leetcode.com/problems/unique-binary-search-trees/
题目原文
Given n, how many structurally unique BST's (binary search trees) that store values 1...n?
For example,
Given n = 3, there are a total of 5 unique BST's.
题目大意
求二叉树的棵数
解题思路
使用动态规划:n=0时,为空树,那么dp[0]=1; n=1时,显然也是1,dp[1]=1;n=2时,dp[2]=2; 对于n>2时,dp[n]=dp[0]dp[n-1]+dp[1]dp[n-2]+......+dp[n-1]*dp[0]
代码
class Solution(object):
def numTrees(self, n):
"""
:type n: int
:rtype: int
"""
dp = [1, 1, 2]
if n <= 2:
return dp[n]
else:
dp += [0 for i in range(n - 2)]
for i in range(3, n + 1):
for j in range(1, i + 1):
dp[i] += dp[j - 1] * dp[i - j]
return dp[n]