zoukankan      html  css  js  c++  java
  • 591

     

     Box of Bricks 

    Little Bob likes playing with his box of bricks. He puts the bricks one upon another and buildsstacks of different height. ``Look, I've built a wall!'', he tells his older sister Alice. ``Nah, you shouldmake all stacks the same height. Then you would have a real wall.'', she retorts. After a little con-sideration, Bob sees that she is right. So he sets out to rearrange the bricks, one by one, such that allstacks are the same height afterwards. But since Bob is lazy he wants to do this with the minimumnumber of bricks moved. Can you help?

    Input 

    The input consists of several data sets. Each set begins with a line containing the number n of stacksBob has built. The next line contains n numbers, the heights h i of the n stacks. You may assume $1 Ÿle n leŸ 50$and $1 leŸ h_i Ÿle 100$.

    The total number of bricks will be divisible by the number of stacks. Thus, it is always possibleto rearrange the bricks such that all stacks have the same height.

    The input is terminated by a set starting with n = 0. This set should not be processed.

    Output 

    For each set, first print the number of the set, as shown in the sample output. Then print the line`` The minimum number of moves is k.'', where k is the minimum number of bricks thathave to be moved in order to make all the stacks the same height.

    Output a blank line after each set.

    Sample Input 

    6
    5 2 4 1 7 5
    0
    

    Sample Output 

    Set #1
    The minimum number of moves is 5.
    
    #include<stdio.h>
    int main(void)
    {
    	int n,i,count=1;
    	while(scanf("%d",&n)&&n)
    	{
    		int h,k=0,sum=0,a[100]={0};
    		for(i=0;i<n;i++) 
    		{scanf("%d",&a[i]);sum+=a[i];}
    		h=sum/n;
    		for(i=0;i<n;i++)
    			if(a[i]>h)
    				k+=a[i]-h;
    		printf("Set #%d
    The minimum number of moves is %d.
    
    ",count++,k);
    	}
    	return 0;
    }


  • 相关阅读:
    ZwQuerySystemInformation的用法
    将十进制整型数转成 2~36(不包含10) 进制数
    简化版C语言文法 130
    Python基础综合练习 130
    编译原理 130
    词法分析 130
    熟悉常用的Linux操作 130
    129有确定性的有穷自动机 130
    实验一.词法分析实验 130
    1.大 数据概述 130
  • 原文地址:https://www.cnblogs.com/snake-hand/p/3148198.html
Copyright © 2011-2022 走看看