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  • 杭电1379--DNA Sorting

    DNA Sorting

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 2185    Accepted Submission(s): 1064


    Problem Description
    One measure of ``unsortedness'' in a sequence is the number of pairs of entries that are out of order with respect to each other. For instance, in the letter sequence ``DAABEC'', this measure is 5, since D is greater than four letters to its right and E is greater than one letter to its right. This measure is called the number of inversions in the sequence. The sequence ``AACEDGG'' has only one inversion (E and D)--it is nearly sorted--while the sequence ``ZWQM'' has 6 inversions (it is as unsorted as can be--exactly the reverse of sorted).

    You are responsible for cataloguing a sequence of DNA strings (sequences containing only the four letters A, C, G, and T). However, you want to catalog them, not in alphabetical order, but rather in order of ``sortedness'', from ``most sorted'' to ``least sorted''. All the strings are of the same length.


    This problem contains multiple test cases!

    The first line of a multiple input is an integer N, then a blank line followed by N input blocks. Each input block is in the format indicated in the problem description. There is a blank line between input blocks.

    The output format consists of N output blocks. There is a blank line between output blocks.

     

     

    Input
    The first line contains two integers: a positive integer n (0 < n <= 50) giving the length of the strings; and a positive integer m (1 < m <= 100) giving the number of strings. These are followed by m lines, each containing a string of length n.
     

     

    Output
    Output the list of input strings, arranged from ``most sorted'' to ``least sorted''. If two or more strings are equally sorted, list them in the same order they are in the input file.
     

     

    Sample Input
    1
    10 6
    AACATGAAGG
    TTTTGGCCAA
    TTTGGCCAAA
    GATCAGATTT
    CCCGGGGGGA
    ATCGATGCAT
     

     

    Sample Output
    CCCGGGGGGA
    AACATGAAGG
    GATCAGATTT
    ATCGATGCAT
    TTTTGGCCAA
    TTTGGCCAAA
     

     

    Source
     

     

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    //输入块之间有空行, 输出块之间也有空行;
     1 #include <stdio.h>
     2 #include <string.h>
     3 #include <algorithm>
     4 using namespace std;
     5 
     6 struct ac
     7 {
     8     int s;
     9     char str[55];
    10 };
    11 ac num[110];
    12 
    13 bool cmp(ac a, ac str)
    14 {
    15     return a.s < str.s;
    16 }
    17 
    18 int main()
    19 {
    20     char ch[55];
    21     int sum, total = 0;
    22     int t, i, j, k, m, n;
    23     scanf("%d", &t);
    24     while(t--)
    25     {
    26         if(total != 0)
    27         printf("
    "); 
    28         scanf("%d %d", &n, &m);
    29         total++ ;
    30         for(i=0; i<m; i++)
    31         {
    32             sum = 0;
    33             scanf("%s", ch);
    34             //puts(ch);
    35             strcpy(num[i].str, ch);
    36             //puts(num[i].str);
    37             for(k=0; k<n-1; k++)
    38             {
    39                 for(j=k+1; j<n; j++)
    40                 {
    41                     if(ch[k] > ch[j])
    42                     sum++;
    43                     //printf("%d %d
    ", k, sum);
    44                 }
    45             }
    46             num[i].s = sum;
    47         }
    48         sort(num, num+m, cmp);
    49         for(i=0; i<m; i++)
    50         printf("%s
    ", num[i].str);
    51         if(t!=0)
    52         printf("
    ");
    53     }
    54     return 0;
    55 }
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  • 原文地址:https://www.cnblogs.com/soTired/p/4676339.html
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