zoukankan      html  css  js  c++  java
  • 杭电2277--Change the ball

    Change the ball

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
    Total Submission(s): 564    Accepted Submission(s): 198


    Problem Description
    Garfield has three piles of balls, each pile has unique color of following: yellow, blue, and red. Now we also know Garfield has Y yellow balls, B blue balls, and R red balls. But Garfield just wants to change all the balls to one color. When he puts two balls of different color togather, the balls then change their colors automatically into the rest color. For instance, when Garfield puts a red one and a yellow one togather, the two balls immediately owns blue color, the same to other situations. But the rule doesn’t work when the two balls have the same color.
      Garfield is not able to estimate the minimal steps to achieve the aim. Can you tell him?

     
    Input
    For each line, there are three intergers Y, B, R(1<=Y,B,R<=1000),indicate the number refered above.
     
    Output
    For each case, tell Garfield the minimal steps to complete the assignment. If not, output the symbol “):”.
     
    Sample Input
    1 2 3
    1 2 2
     
    Sample Output
    ):
    2
     
    Source
     
    Recommend
    lcy   |   We have carefully selected several similar problems for you:  2273 2276 2274 2279 2275 
    分析:三个数中只要有两个数之差为3的倍数就可以完成转化; 转化次数为num=max(a, b); 结果为min(num) ; 
     1 #include <stdio.h>
     2 #include <math.h>
     3 #include <algorithm>
     4 #define max(a,b) a>b?a:b 
     5 using namespace std;
     6 int main()
     7 {
     8 
     9     int a, b, c;
    10     int i, total;
    11     
    12     while(~scanf("%d %d %d", &a, &b, &c))
    13     {
    14         total = 0;
    15         int num[3] = {0, 0, 0};
    16         if(abs(a-b)%3==0)
    17             num[total] += max(a,b);
    18         total++;
    19         if(abs(b-c)%3==0)
    20             num[total] += max(b,c);
    21         total++;
    22         if(abs(a-c)%3==0)
    23             num[total] += max(a,c);
    24         total++;
    25         if(num[0]==0 && num[1]==0 && num[2]==0)
    26           printf("):
    ");
    27         else
    28         {
    29             sort(num, num+3);
    30             for(i=0; i<3; i++)
    31             {
    32                 if(num[i] != 0)
    33                 {
    34                     printf("%d
    ",num[i]);
    35                     break; 
    36                 }
    37             }
    38         }
    39     }
    40     return 0;
    41 }
     
  • 相关阅读:
    openlayers方法总结
    AJAX 数据库实例
    AJAX 请求服务器
    得到XMLHttpRequest对象
    AJAX 简介
    AJAX 服务器端的脚本
    HTTP GET 最多发送100个字符
    AJAX XMLHttpRequest 对象
    Dictionary、ArrayList、Hashtable和数组 Array 的区别
    AJAX 请求实例
  • 原文地址:https://www.cnblogs.com/soTired/p/4677421.html
Copyright © 2011-2022 走看看