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  • Lightoj1043--Triangle Partitioning(水数学)

    Triangle Partitioning
           
    Time Limit: 0.5 second(s) Memory Limit: 32 MB

    See the picture below.

     

    You are given ABAC and BCDE is parallel to BC. You are also given the area ratio between ADE and BDEC. You have to find the value of AD.

    Input

    Input starts with an integer T (≤ 25), denoting the number of test cases.

    Each case begins with four real numbers denoting AB, AC, BC and the ratio of ADE and BDEC (ADE / BDEC). You can safely assume that the given triangle is a valid triangle with positive area.

    Output

    For each case of input you have to print the case number and AD. Errors less than 10-6 will be ignored.

    Sample Input

    Output for Sample Input

    4

    100 100 100 2

    10 12 14 1

    7 8 9 10

    8.134 9.098 7.123 5.10

    Case 1: 81.6496580

    Case 2: 7.07106781

    Case 3: 6.6742381247

    Case 4: 7.437454786

    简直就是大神们秀智商的天堂。

    #include <cmath> 
    #include <cstdio>
    int main(){
        int t, Tim = 1;
        scanf("%d", &t);
        while(t--){
            double a, b, c, d;
            scanf("%lf%lf%lf%lf", &a, &b, &c, &d);
            double temp = sqrt(d/(d+1));
            printf("Case %d: %.6lf
    ", Tim++, temp*a);
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/soTired/p/5024258.html
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