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  • HDU6668 Polynomial(模拟)

    HDU6668 Polynomial

    顺序遍历找出最高次幂项的系数

    分三种情况 (1/0)(0/1)(f(x)/g(x))

    复杂度为 (O(n))

    #include<stdio.h>
    #include<stdlib.h>
    #include<math.h>
    #include<algorithm>
    
    using namespace std;
    
    const int maxn = 1005;
    int t, n, f_num, f_id, g_num, g_id;
    int f[maxn], g[maxn];
    
    int gcd(int a, int b){
        return b ? gcd(b, a % b) : a;
    }
    int main()
    {
        scanf("%d", &t);
        for(int cas = 1; cas <= t; cas++){
            scanf("%d", &n);
            f_id = g_id = 0;
            for(int i = 1; i <= n; i++){
                scanf("%d", &f[i]);
                if(f[i] > 0){
                    f_num = f[i];
                    f_id = i;
                }
            }
            for(int i = 1; i <= n; i++){
                scanf("%d", &g[i]);
                if(g[i] > 0){
                    g_num = g[i];
                    g_id = i;
                }
            }
            if(f_id < g_id){
                puts("0/1");
            }
            else if(f_id > g_id){
                puts("1/0");
            }
            else{
                int d = gcd(f_num, g_num);
                printf("%d/%d
    ", f_num / d, g_num / d);
            }
        }
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/solvit/p/11372928.html
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