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  • 算法(Algorithms)第4版 练习 2.2.11(3)

    关键代码实现:

      public static void sort(Comparable[] input) {
            int N = input.length;
            aux = input.clone();//must be clone(the same as input)
    //        StdOut.println("input:" + input + " aux:" + aux);//for test
            sort(aux, input, 0, N-1);
        }
        
        //take input from source, sort it and put output in destination
        //source and destination is the same at the beginning
        private static void sort(Comparable[] source, Comparable[] destination, int lo, int hi) {
            
            if(lo >= hi)//just one entry in array
                return;
            
            int mid = lo + (hi-lo)/2;
            sort(destination, source, lo, mid);//first get input from destination, sort it and put output in source
            sort(destination, source, mid+1, hi);
            merge(source, destination, lo, mid, hi);//merge sorted source to destination
            
        }
        
        private static void merge(Comparable[] source, Comparable[] destination, int lo, int mid, int hi) {
            
            int i = lo;
            int j = mid + 1;
            for(int k = lo; k <= hi; k++) {
                if(i > mid)
                    destination[k] = source[j++];
                else if(j > hi)
                    destination[k] = source[i++];
                else if(less(source[j], source[i]))
                    destination[k] = source[j++];
                else 
                    destination[k] = source[i++];
            }
    //        StdOut.println("source:" + source + " destination:" + destination);
    //        StdOut.printf("merge(source, destination, %4d, %4d, %4d)", lo, mid, hi);
    //        show(destination);//for test
            
        }

    测试用例:

    package com.qiusongde;
    
    import edu.princeton.cs.algs4.In;
    import edu.princeton.cs.algs4.StdOut;
    
    public class MergeAvoidCopy {
        
        private static Comparable[] aux;
        
        public static void sort(Comparable[] input) {
            int N = input.length;
            aux = input.clone();//must be clone(the same as input)
    //        StdOut.println("input:" + input + " aux:" + aux);//for test
            sort(aux, input, 0, N-1);
        }
        
        //take input from source, sort it and put output in destination
        //source and destination is the same in start
        private static void sort(Comparable[] source, Comparable[] destination, int lo, int hi) {
            
            if(lo >= hi)//just one entry in array
                return;
            
            int mid = lo + (hi-lo)/2;
            sort(destination, source, lo, mid);//first get input from destination, sort it and put output in source
            sort(destination, source, mid+1, hi);
            merge(source, destination, lo, mid, hi);//merge sorted source to destination
            
        }
        
        private static void merge(Comparable[] source, Comparable[] destination, int lo, int mid, int hi) {
            
            int i = lo;
            int j = mid + 1;
            for(int k = lo; k <= hi; k++) {
                if(i > mid)
                    destination[k] = source[j++];
                else if(j > hi)
                    destination[k] = source[i++];
                else if(less(source[j], source[i]))
                    destination[k] = source[j++];
                else 
                    destination[k] = source[i++];
            }
    //        StdOut.println("source:" + source + " destination:" + destination);
    //        StdOut.printf("merge(source, destination, %4d, %4d, %4d)", lo, mid, hi);
    //        show(destination);//for test
            
        }
        
        private static boolean less(Comparable v, Comparable w) {
            
            return v.compareTo(w) < 0;
            
        }
        
        private static void show(Comparable[] a) {
            
            //print the array, on a single line.
            for(int i = 0; i < a.length; i++) {
                StdOut.print(a[i] + " ");
            }
            StdOut.println();
            
        }
        
        public static boolean isSorted(Comparable[] a) {
            
            for(int i = 1; i < a.length; i++) {
                if(less(a[i], a[i-1]))
                    return false;
            }
            
            return true;
            
        }
        
        public static void main(String[] args) {
            
            //Read strings from standard input, sort them, and print.
            String[] input = In.readStrings();
    //        show(input);//for test
            sort(input);
            assert isSorted(input);
    //        show(input);//for test
            
        }
    
    }

    测试结果:

    M E R G E S O R T E X A M P L E 
    input:[Ljava.lang.String;@1b6d3586 aux:[Ljava.lang.String;@4554617c
    source:[Ljava.lang.String;@1b6d3586 destination:[Ljava.lang.String;@4554617c
    merge(source, destination,    0,    0,    1)E M R G E S O R T E X A M P L E 
    source:[Ljava.lang.String;@1b6d3586 destination:[Ljava.lang.String;@4554617c
    merge(source, destination,    2,    2,    3)E M G R E S O R T E X A M P L E 
    source:[Ljava.lang.String;@4554617c destination:[Ljava.lang.String;@1b6d3586
    merge(source, destination,    0,    1,    3)E G M R E S O R T E X A M P L E 
    source:[Ljava.lang.String;@1b6d3586 destination:[Ljava.lang.String;@4554617c
    merge(source, destination,    4,    4,    5)E M G R E S O R T E X A M P L E 
    source:[Ljava.lang.String;@1b6d3586 destination:[Ljava.lang.String;@4554617c
    merge(source, destination,    6,    6,    7)E M G R E S O R T E X A M P L E 
    source:[Ljava.lang.String;@4554617c destination:[Ljava.lang.String;@1b6d3586
    merge(source, destination,    4,    5,    7)E G M R E O R S T E X A M P L E 
    source:[Ljava.lang.String;@1b6d3586 destination:[Ljava.lang.String;@4554617c
    merge(source, destination,    0,    3,    7)E E G M O R R S T E X A M P L E 
    source:[Ljava.lang.String;@1b6d3586 destination:[Ljava.lang.String;@4554617c
    merge(source, destination,    8,    8,    9)E E G M O R R S E T X A M P L E 
    source:[Ljava.lang.String;@1b6d3586 destination:[Ljava.lang.String;@4554617c
    merge(source, destination,   10,   10,   11)E E G M O R R S E T A X M P L E 
    source:[Ljava.lang.String;@4554617c destination:[Ljava.lang.String;@1b6d3586
    merge(source, destination,    8,    9,   11)E G M R E O R S A E T X M P L E 
    source:[Ljava.lang.String;@1b6d3586 destination:[Ljava.lang.String;@4554617c
    merge(source, destination,   12,   12,   13)E E G M O R R S E T A X M P L E 
    source:[Ljava.lang.String;@1b6d3586 destination:[Ljava.lang.String;@4554617c
    merge(source, destination,   14,   14,   15)E E G M O R R S E T A X M P E L 
    source:[Ljava.lang.String;@4554617c destination:[Ljava.lang.String;@1b6d3586
    merge(source, destination,   12,   13,   15)E G M R E O R S A E T X E L M P 
    source:[Ljava.lang.String;@1b6d3586 destination:[Ljava.lang.String;@4554617c
    merge(source, destination,    8,   11,   15)E E G M O R R S A E E L M P T X 
    source:[Ljava.lang.String;@4554617c destination:[Ljava.lang.String;@1b6d3586
    merge(source, destination,    0,    7,   15)A E E E E G L M M O P R R S T X 
    A E E E E G L M M O P R R S T X 

    性能比较:

    For 20000 random Doubles 1000 trials
    Merge is 3.4s
    MergeFasterM is 3.1s
    MergeUseInsert is 3.2s
    MergeSkipMerge is 3.3s
    MergeAvoidCopy is 3.0s
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  • 原文地址:https://www.cnblogs.com/songdechiu/p/6613514.html
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