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  • 【Codechef】—Walk on Tree(BM+常系数线性递推)

    传送门


    O(n3logk)O(n^3logk)的做法很显然

    考虑说实际上是要求对矩阵的某些位置求和
    实际上这个是有递推式的,而且递推式就是矩阵的特征多项式

    实际很显然的每次都是对特征多项式取模
    一个位置就是寻常的常系数线性递推
    对一些位置求和的话也是一样满足的

    暴力dpdp把前nn项搞出来然后BMBM水过去

    #include<bits/stdc++.h>
    using namespace std;
    #define gc getchar
    inline int read(){
    	char ch=gc();
    	int res=0,f=1;
    	while(!isdigit(ch))f^=ch=='-',ch=gc();
    	while(isdigit(ch))res=(res+(res<<2)<<1)+(ch^48),ch=gc();
    	return f?res:-res;
    }
    #define pb push_back
    #define cs const
    #define ll long long
    #define poly vector<int>
    #define bg begin
    cs int mod=998244353,G=3;
    inline int add(int a,int b){return (a+=b)>=mod?a-mod:a;}
    inline void Add(int &a,int b){(a+=b)>=mod?(a-=mod):0;}
    inline int dec(int a,int b){return (a-=b)<0?a+mod:a;}
    inline void Dec(int &a,int b){(a-=b)<0?(a+=mod):0;}
    inline int mul(int a,int b){return 1ll*a*b>=mod?1ll*a*b%mod:a*b;}
    inline void Mul(int &a,int b){a=mul(a,b);}
    inline int ksm(int a,int b,int res=1){
    	for(;b;b>>=1,a=mul(a,a))(b&1)&&(res=mul(res,a));return res;
    }
    inline void chemx(ll &a,ll b){a<b?a=b:0;}
    inline void chemn(ll &a,ll b){a>b?a=b:0;}
    cs int N=(1<<17)|5,C=17;
    poly w[C+1];
    inline void init_w(){
    	for(int i=1;i<=C;i++)w[i].resize(1<<(i-1));
    	int wn=ksm(G,(mod-1)/(1<<C));
    	w[C][0]=1;
    	for(int i=1;i<(1<<(C-1));i++)w[C][i]=mul(w[C][i-1],wn);
    	for(int i=C-1;i;i--)
    	for(int j=0;j<(1<<(i-1));j++)
    	w[i][j]=w[i+1][j<<1];
    }
    int rev[N];
    inline void init_rev(int lim){
    	for(int i=0;i<lim;i++)rev[i]=(rev[i>>1]>>1)|((i&1)*(lim>>1));
    }
    inline void ntt(poly &f,int lim,int kd){
    	for(int i=0;i<lim;i++)if(i>rev[i])swap(f[i],f[rev[i]]);
    	for(int a0,a1,mid=1,l=1;mid<lim;mid<<=1,l++)
    	for(int i=0;i<lim;i+=(mid<<1))
    	for(int j=0;j<mid;j++)
    	a0=f[i+j],a1=mul(w[l][j],f[i+j+mid]),f[i+j]=add(a0,a1),f[i+j+mid]=dec(a0,a1);
    	if(kd==-1){
    		reverse(f.bg()+1,f.bg()+lim);
    		for(int i=0,inv=ksm(lim,mod-2);i<lim;i++)Mul(f[i],inv);
    	}
    }
    inline poly operator +(poly a,poly b){
    	int deg=max(a.size(),b.size());
    	a.resize(deg),b.resize(deg);
    	for(int i=0;i<deg;i++)Add(a[i],b[i]);
    	return a;
    }
    inline poly operator -(poly a,poly b){
    	int deg=max(a.size(),b.size());
    	a.resize(deg),b.resize(deg);
    	for(int i=0;i<deg;i++)Dec(a[i],b[i]);
    	return a;
    }
    inline poly operator *(poly a,poly b){
    	int deg=a.size()+b.size()-1,lim=1;
    	if(deg<128){
    		poly c(deg,0);
    		for(int i=0;i<a.size();i++)
    		for(int j=0;j<b.size();j++)
    		Add(c[i+j],mul(a[i],b[j]));
    		return c;
    	}
    	while(lim<deg)lim<<=1;
    	init_rev(lim);
    	a.resize(lim),ntt(a,lim,1);
    	b.resize(lim),ntt(b,lim,1);
    	for(int i=0;i<lim;i++)Mul(a[i],b[i]);
    	ntt(a,lim,-1),a.resize(deg);
    	return a;
    }
    inline poly Inv(poly a,int deg){
    	poly b(1,ksm(a[0],mod-2)),c;
    	for(int lim=4;lim<(deg<<2);lim<<=1){
    		c=a,c.resize(lim>>1);
    		init_rev(lim);
    		b.resize(lim),c.resize(lim);
    		ntt(b,lim,1),ntt(c,lim,1);
    		for(int i=0;i<lim;i++)Mul(b[i],dec(2,mul(b[i],c[i])));
    		ntt(b,lim,-1),b.resize(lim>>1);
    	}b.resize(deg);
    	return b;
    }
    inline poly operator /(poly a,poly b){
    	int deg=(int)a.size()-(int)b.size()+1;
    	if(deg<0)return poly(1,0);
    	reverse(a.bg(),a.end());
    	reverse(b.bg(),b.end());
    	a.resize(deg),b.resize(deg);
    	poly c=a*Inv(b,deg);c.resize(deg);
    	reverse(c.bg(),c.end());
    	return c;
    }
    inline poly operator %(poly a,poly b){
    	if(a.size()<b.size())return a;
    	a=a-(a/b)*b;a.resize(b.size()-1);return a;
    }
    inline poly ksm(poly a,int b,poly res,poly Mod){
    	for(;b;b>>=1,a=a*a%Mod)if(b&1)res=res*a%Mod;
    	return res;
    }
    namespace Cas{
    	poly f;int n;
    	inline void init(poly coef){
    		init_w();
    		n=coef.size();
    		f.resize(n+1);
    		for(int i=1;i<=n;i++)f[n-i]=mod-coef[i];
    		f[n]=1;
    	}
    	inline poly calc(int k){
    		poly g(2),res(1,1);g[1]=1;
    		res=ksm(g,k,res,f);
    		return res;
    	}
    }
    namespace B_M{
    	poly r[N];
    	int fail[N],del[N],a[N],n,cnt;
    	inline void update(int i){
    		cnt++;
    		int Mu=mul(dec(del[i],a[i]),ksm(dec(del[fail[cnt-2]],a[fail[cnt-2]]),mod-2));
    		r[cnt].resize(i-fail[cnt-2],0);
    		r[cnt].pb(Mu);
    		for(int j=1;j<r[cnt-2].size();j++)
    		r[cnt].pb(mul(Mu,mod-r[cnt-2][j]));
    		r[cnt]=r[cnt]+r[cnt-1];
    	}
    	inline void BM(){
    		for(int i=1;i<=n;i++){
    			for(int j=1;j<r[cnt].size();j++)
    			Add(del[i],mul(r[cnt][j],a[i-j]));
    			if(del[i]!=a[i]){
    				fail[cnt]=i;
    				if(!cnt)r[++cnt].resize(i);
    				else update(i);
    			}
    		}
    		Cas::init(r[cnt]);
    	}
    	inline void init(int *v,int len){
    		n=len;
    		for(int i=1;i<=n;i++)a[i]=v[i-1];
    		BM();
    	}
    }
    vector<int> e[3005];
    int f[3005][6005];
    int n,K,rt,lim;
    int main(){
    	n=read(),lim=2*n;
    	for(int i=1;i<n;i++){
    		int u=read(),v=read();
    		e[u].pb(v),e[v].pb(u);
    	}
     	rt=read(),K=read();	
     	f[rt][0]=1;
     	for(int i=0;i<lim;i++)
     	for(int u=1;u<=n;u++)if(f[u][i])
     	for(int &v:e[u])Add(f[v][i+1],f[u][i]);
     	B_M::init(f[rt],lim);
     	poly res=Cas::calc(K);
     	for(int i=1;i<=n;i++){
     		int anc=0;
     		for(int j=0;j<res.size();j++)Add(anc,mul(f[i][j],res[j]));
     		cout<<anc<<" ";
    	 }
    }
    
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  • 原文地址:https://www.cnblogs.com/stargazer-cyk/p/12328676.html
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