寻找水王

思路：根据老师上课提示的“相互消去”的方法，因为水王的发帖子的数量超过一半，所以两个不同的帖子消去，最后剩下的肯定就是水王的id

#include<iostream.h>
#include "stdlib.h"
int main()
{
    int length;
    int Idnum[3]={0,0,0};
    int ID[3]={0,0,0};     
    cout<<"请输入总帖子数量："<<endl;
    cin>>length;
    int * curId=new int [length];
     cout<<"请输入水军的ID列表"<<endl;
    for(int j=0;j<length;j++)
    {
        cin>>curId[j];
    }
    for(int i=0;i<length;i++)
    {
        if(Idnum[0]==0 && curId[i]!=ID[1] && curId[i]!=ID[2])
        {
            Idnum[0]=1;
            ID[0]=curId[i];
        }
        else if(Idnum[1]==0 && curId[i]!=ID[0] && curId[i]!=ID[2])
        {
            Idnum[1]=1;
            ID[1]=curId[i];
        }
        else if(Idnum[2]==0 && curId[i]!=ID[0] && curId[i]!=ID[1])
        {
            Idnum[2]=1;
            ID[2]=curId[i];
        }
        else if(curId[i]!=ID[0] && curId[i]!=ID[1] && curId[i]!=ID[2])
        {
            Idnum[0]--;
            Idnum[1]--;
            Idnum[2]--;
        }
        else if(curId[i]==ID[0])
        {
            Idnum[0]++;
        }
        else if(curId[i]==ID[1])
        {
            Idnum[1]++;
        }
        else if(curId[i]==ID[2])
        {
            Idnum[2]++;
        }      
    }
    cout<<"三个水桶ID为："<<ID[0]<<" "<<ID[1]<<" "<<ID[2]<<" "<<endl;+
    return 0;
}