普通递归版本二分法
def binary_search(n, left, right):
if left <= right:
middle = (left+right) // 2
if n < lst[middle]:
right = middle - 1
elif n > lst[middle]:
left = middle + 1
else:
return middle
return binary_search(n, left, right) # 这个return必须要加. 否则接收 到的永远是None.
else:
return -1
print(binary_search(567, 0, len(lst)-1))
另类二分法(很难计算位置):
def binary_search(ls, target):
left = 0
right = len(ls) - 1
if left > right:
print("不在这里")
middle = (left + right) // 2
if target < ls[middle]:
return binary_search(ls[:middle], target)
elif target > ls[middle]:
return binary_search(ls[middle+1:], target)
else:
print("在这⾥里里")
binary_search(lst, 567)