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  • 数学趣题——递归法求幂

       1: #include "stdio.h"
       2:  
       3: unsigned long myPow(int m, int n)
       4: {
       5:     unsigned long tmp;
       6:  
       7:     if(n == 0) return 1;
       8:  
       9:     if(n == 1) return m;
      10:  
      11:     if(n % 2 == 0) {
      12:         tmp = myPow(m, n / 2);
      13:         return tmp * tmp;
      14:     }
      15:  
      16:     if(n % 2 != 0)
      17:         return m * myPow(m, n - 1);
      18: }
      19:  
      20: int main()
      21: {
      22:     int m, n;
      23:     printf("Please input the bottom number\n");
      24:     scanf("%d", &m);                            /*输入底数m*/
      25:     printf("Please input the exponent number\n");
      26:     scanf("%d", &n);                            /*输入指数n*/
      27:     printf("The result of power(m,n) is %ld\n", myPow(m, n));        /*输出计算结果mn*/
      28:     return 0;
      29: }
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  • 原文地址:https://www.cnblogs.com/steven_oyj/p/1745012.html
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