zoukankan      html  css  js  c++  java
  • [Swift]LeetCode243.最短单词距离 $ Shortest Word Distance

    ★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★
    ➤微信公众号:山青咏芝(shanqingyongzhi)
    ➤博客园地址:山青咏芝(https://www.cnblogs.com/strengthen/
    ➤GitHub地址:https://github.com/strengthen/LeetCode
    ➤原文地址:https://www.cnblogs.com/strengthen/p/10213804.html 
    ➤如果链接不是山青咏芝的博客园地址,则可能是爬取作者的文章。
    ➤原文已修改更新!强烈建议点击原文地址阅读!支持作者!支持原创!
    ★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★

    Given a list of words and two words word1 and word2, return the shortest distance between these two words in the list.

    For example,
    Assume that words = ["practice", "makes", "perfect", "coding", "makes"].

    Given word1 = “coding”word2 = “practice”, return 3.
    Given word1 = "makes"word2 = "coding", return 1.

    Note:
    You may assume that word1 does not equal to word2, and word1 and word2 are both in the list.


    给定单词列表以及单词1和单词2,返回列表中这两个单词之间的最短距离。

    例如,

    假设words=[“practice”、“makes”、“perfect”、“coding”、“makes”]。

    给定word1=“coding”,word2=“practice”,返回3。

    给定word1=“makes”,word2=“coding”,返回1。

    注:

    您可以假定word1不等于word2,word1和word2都在列表中。


     1 class Solution {
     2     func shortestDistance(_ words: [String],_ word1:String,_ word2:String) -> Int {
     3         var idx:Int = -1
     4         var res:Int = Int.max
     5         for i in 0..<words.count
     6         {
     7             if words[i] == word1 || words[i] == word2
     8             {
     9                 if idx != -1 && words[idx] != words[i]
    10                 {
    11                     res = min(res, i - idx)
    12                 }
    13                 idx = i
    14             }
    15         }
    16         return res
    17     }
    18 }
  • 相关阅读:
    BGP
    ospf路由认证
    rip路由认证
    php-数组的相关函数及排序算法
    php-多维数组,数组遍历
    php-数组的概念,语法及特点
    php-错误处理
    MySQL性能优化
    JUC多线程03
    JUC多线程01
  • 原文地址:https://www.cnblogs.com/strengthen/p/10213804.html
Copyright © 2011-2022 走看看