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  • [Swift]LeetCode368. 最大整除子集 | Largest Divisible Subset

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    ➤原文地址:https://www.cnblogs.com/strengthen/p/10277728.html 
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    Given a set of distinct positive integers, find the largest subset such that every pair (Si, Sj) of elements in this subset satisfies:

    Si % Sj = 0 or Sj % Si = 0.

    If there are multiple solutions, return any subset is fine.

    Example 1:

    Input: [1,2,3]
    Output: [1,2] (of course, [1,3] will also be ok)
    

    Example 2:

    Input: [1,2,4,8]
    Output: [1,2,4,8]

    给出一个由无重复的正整数组成的集合,找出其中最大的整除子集,子集中任意一对 (Si,Sj) 都要满足:Si % Sj = 0 或 Sj % Si = 0。

    如果有多个目标子集,返回其中任何一个均可。 

    示例 1:

    输入: [1,2,3]
    输出: [1,2] (当然, [1,3] 也正确)
    

    示例 2:

    输入: [1,2,4,8]
    输出: [1,2,4,8]

    476ms
     1 class Solution {
     2     func largestDivisibleSubset(_ nums: [Int]) -> [Int] {
     3         var nums = nums.sorted(by:<)
     4         var res:[Int] = [Int]()
     5         let number:Int = nums.count
     6         var dp:[[Int]] = [[Int]](repeating:[Int](repeating:0,count:2),count:number)
     7         var mx:Int = 0
     8         var mx_idx:Int = 0
     9         for i in 0..<number
    10         {
    11             for j in stride(from:i,through:0,by:-1)
    12             {
    13                 if nums[i] % nums[j] == 0 && dp[i][0] < dp[j][0] + 1
    14                 {
    15                     dp[i][0] = dp[j][0] + 1
    16                     dp[i][1] = j
    17                     if mx < dp[i][0]
    18                     {
    19                         mx = dp[i][0]
    20                         mx_idx = i
    21                     }                    
    22                 }
    23             }
    24         }
    25         for i in 0..<mx
    26         {
    27             res.append(nums[mx_idx])
    28             mx_idx = dp[mx_idx][1]            
    29         }
    30         return res
    31     }
    32 }
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  • 原文地址:https://www.cnblogs.com/strengthen/p/10277728.html
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