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  • [Swift]LeetCode833. 字符串中的查找与替换 | Find And Replace in String

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    To some string S, we will perform some replacement operations that replace groups of letters with new ones (not necessarily the same size).

    Each replacement operation has 3parameters: a starting index i, a source word x and a target word y.  The rule is that if x starts at position i in the originalstring S, then we will replace that occurrence of x with y.  If not, we do nothing.

    For example, if we have S = "abcd" and we have some replacement operation i = 2, x = "cd", y = "ffff", then because "cd" starts at position 2 in the original string S, we will replace it with "ffff".

    Using another example on S = "abcd", if we have both the replacement operation i = 0, x = "ab", y = "eee", as well as another replacement operation i = 2, x = "ec", y = "ffff", this second operation does nothing because in the original string S[2] = 'c', which doesn't match x[0] = 'e'.

    All these operations occur simultaneously.  It's guaranteed that there won't be any overlap in replacement: for example, S = "abc", indexes = [0, 1], sources = ["ab","bc"] is not a valid test case.

    Example 1:

    Input: S = "abcd", indexes = [0,2], sources = ["a","cd"], targets = ["eee","ffff"]
    Output: "eeebffff"
    Explanation: "a" starts at index 0 in S, so it's replaced by "eee".
    "cd" starts at index 2 in S, so it's replaced by "ffff".
    

    Example 2:

    Input: S = "abcd", indexes = [0,2], sources = ["ab","ec"], targets = ["eee","ffff"]
    Output: "eeecd"
    Explanation: "ab" starts at index 0 in S, so it's replaced by "eee". 
    "ec" doesn't starts at index 2 in the original S, so we do nothing.
    

    Notes:

    1. 0 <= indexes.length = sources.length = targets.length <= 100
    2. 0 < indexes[i] < S.length <= 1000
    3. All characters in given inputs are lowercase letters.

    对于某些字符串 S,我们将执行一些替换操作,用新的字母组替换原有的字母组(不一定大小相同)。

    每个替换操作具有 3 个参数:起始索引 i,源字 x 和目标字 y。规则是如果 x 从原始字符串 S 中的位置 i 开始,那么我们将用 y 替换出现的 x。如果没有,我们什么都不做。

    举个例子,如果我们有 S = “abcd” 并且我们有一些替换操作 i = 2,x = “cd”,y = “ffff”,那么因为 “cd” 从原始字符串 S 中的位置 2 开始,我们将用 “ffff”替换它。

    再来看 S = “abcd” 上的另一个例子,如果我们有替换操作 i = 0,x = “ab”,y = “eee”,以及另一个替换操作 i = 2,x = “ec”,y = “ffff”,那么第二个操作将不执行任何操作,因为原始字符串中 S[2] = 'c',与 x[0] = 'e' 不匹配。

    所有这些操作同时发生。保证在替换时不会有任何重叠: S = "abc", indexes = [0, 1], sources = ["ab","bc"] 不是有效的测试用例。

    示例 1:

    输入:S = "abcd", indexes = [0,2], sources = ["a","cd"], targets = ["eee","ffff"]
    输出:"eeebffff"
    解释:
    "a" 从 S 中的索引 0 开始,所以它被替换为 "eee"。
    "cd" 从 S 中的索引 2 开始,所以它被替换为 "ffff"。
    

    示例 2:

    输入:S = "abcd", indexes = [0,2], sources = ["ab","ec"], targets = ["eee","ffff"]
    输出:"eeecd"
    解释:
    "ab" 从 S 中的索引 0 开始,所以它被替换为 "eee"。
    "ec" 没有从原始的 S 中的索引 2 开始,所以它没有被替换。 

    提示:

    1. 0 <= indexes.length = sources.length = targets.length <= 100
    2. 0 < indexes[i] < S.length <= 1000
    3. 给定输入中的所有字符都是小写字母。

    36ms

     1 final class Solution {
     2     func findReplaceString(_ S: String, _ indexes: [Int], _ sources: [String], _ targets: [String]) -> String {
     3         var dict: [Int: (String, String)] = Dictionary(uniqueKeysWithValues: zip(indexes, zip(sources, targets)) )
     4         var indexes = indexes.sorted(by: >)
     5         var S = Array(S)
     6         var res = S
     7         for index in indexes {
     8             let val = dict[index]!
     9             let source = Array(val.0)
    10             let target = Array(val.1)
    11             if hasOccurence(S, source, index) {
    12                 res.replaceSubrange(index..<(index &+ source.count), with: target)
    13             }
    14         }
    15         return String(res)
    16     }
    17     
    18     @inline(__always) private func hasOccurence(_ S: [Character], _ source: [Character], _ index: Int) -> Bool {
    19         for i in index..<(index + source.count) {
    20             if i >= S.count { return false }
    21             if S[i] != source[i - index] { return false }
    22         }
    23         return true
    24     }
    25 }

    40ms

     1 class Solution {    
     2     struct StringReplaceIndex: Comparable {
     3         let index: Int
     4         let source: String
     5         let target: String
     6 
     7         static func < (lhs: StringReplaceIndex, rhs: StringReplaceIndex) -> Bool {
     8             return lhs.index < rhs.index
     9         }
    10     }
    11 
    12     func findReplaceString(_ S: String, _ indices: [Int], _ sources: [String], _ targets: [String]) -> String {
    13         // build the replace indices in sorted order
    14         var replaceIndices = [StringReplaceIndex]()
    15         for i in 0..<indices.count {
    16             replaceIndices.append(StringReplaceIndex(index: indices[i], source: sources[i], target: targets[i]))
    17         }
    18         replaceIndices.sort()
    19 
    20         var result = [String]()
    21 
    22         // need to handle the substring when the indices doesn't start from 0
    23         if replaceIndices[0].index != 0 {
    24             let subString = S.subString(from: 0, to: replaceIndices[0].index - 1)
    25             result.append(subString)
    26         }
    27 
    28         for i in 0..<replaceIndices.count {
    29             let startIndex = replaceIndices[i].index
    30             let endIndex = ((i+1) < replaceIndices.count) ? replaceIndices[i+1].index - 1 : S.count - 1
    31             var subString = S.subString(from: startIndex, to: endIndex)
    32             if subString.hasPrefix(replaceIndices[i].source) {
    33                 subString.removeFirst(replaceIndices[i].source.count)
    34                 subString = replaceIndices[i].target + subString
    35             }
    36             result.append(subString)
    37         }
    38         return result.reduce("", +)
    39     }        
    40 }
    41     
    42 extension String {
    43 
    44     subscript(i: Int) -> Character {
    45         get {
    46             return self[index(startIndex, offsetBy: i)]
    47         }
    48     }
    49 
    50     func subString(from: Int, to: Int) -> String {
    51         guard from <= to else {
    52             return ""
    53         }
    54 
    55         let startIndex = self.index(self.startIndex, offsetBy: from)
    56         let endIndex = self.index(self.startIndex, offsetBy: to)
    57         return String(self[startIndex...endIndex])
    58     }
    59 
    60     func subString(from: Int) -> String {
    61         let startIndex = self.index(self.startIndex, offsetBy: from)
    62         return String(self.suffix(from: startIndex))
    63     }
    64 
    65     func asciiValues() -> [Int] {
    66         return Array(self.utf16).map { Int($0) }
    67     }
    68 
    69     mutating func lTrim(_ regex: String = "^\s+") {
    70         if let trailingSpacesRange = self.range(of: regex, options: .regularExpression) {
    71             self.replaceSubrange(trailingSpacesRange, with: "")
    72         }
    73     }
    74 
    75     mutating func rTrim(_ regex: String = "\s+$") {
    76         if let trailingSpacesRange = self.range(of: regex, options: .regularExpression) {
    77             self.replaceSubrange(trailingSpacesRange, with: "")
    78         }
    79     }
    80 
    81     func stringByReplacingAt(_ index: Int, with ch: Character) -> String {
    82         var chars = Array(self)
    83         chars[index] = ch
    84         let modifiedString = String(chars)
    85         return modifiedString
    86     }
    87 }

    48ms

     1 class Solution {
     2     private struct ConfirmedReplacement {
     3         let start: String.Index
     4         let end: String.Index
     5         let target: String
     6     }
     7     
     8     func findReplaceString(_ S: String, _ indexes: [Int], _ sources: [String], _ targets: [String]) -> String {
     9         var confirmedTargets: [ConfirmedReplacement] = []
    10         //1. confirm
    11         for i in 0..<indexes.count {
    12             let start = S.index(S.startIndex, offsetBy: indexes[i])
    13             let source = sources[i]
    14             let end = S.index(start, offsetBy: source.count)
    15             let target = targets[i]
    16             if S[start..<end] != source {
    17                 continue
    18             }
    19             let confirmed = ConfirmedReplacement(start: start, end: end, target: target)
    20             confirmedTargets.append(confirmed)
    21         }
    22         //2. sort confirmed range
    23         confirmedTargets = confirmedTargets.sorted(by: { (lhs, rhs) -> Bool in
    24             return rhs.start > lhs.start
    25         })
    26         //3. fill string
    27         var strFragments: [String] = []
    28         var index = S.startIndex
    29         for target in confirmedTargets {
    30             strFragments.append(String(S[index..<target.start]))
    31             strFragments.append(target.target)
    32             index = target.end
    33         }
    34         strFragments.append(String(S[index..<S.endIndex]))
    35         return strFragments.joined()
    36     }
    37 }

    Runtime: 60 ms
    Memory Usage: 19.7 MB
     1 class Solution {
     2     func findReplaceString(_ S: String, _ indexes: [Int], _ sources: [String], _ targets: [String]) -> String {
     3         var S = S
     4         var v:[[Int]] = [[Int]]()
     5         for i in 0..<indexes.count
     6         {
     7             v.append([indexes[i], i])
     8         }
     9         v.sort(by:{(a:[Int],b:[Int]) -> Bool in 
    10                    if a[0] == b[0]
    11                    {
    12                        return a[1] >= b[1]
    13                    }
    14                    else
    15                    {
    16                        return a[0] > b[0]
    17                    }
    18                   })
    19         for a in v
    20         {
    21             var i:Int = a.first!
    22             var str:String = sources[a[1]]
    23             var t:String = targets[a[1]]
    24             if S.subString(i, str.count) == str
    25             {
    26                 S = S.subString(0, i) + t + S.subString(i + str.count)
    27             }
    28         }
    29         return S
    30     }
    31 }
    32 
    33 extension String {
    34     // 截取字符串:从index到结束处
    35     // - Parameter index: 开始索引
    36     // - Returns: 子字符串
    37     func subString(_ index: Int) -> String {
    38         let theIndex = self.index(self.endIndex, offsetBy: index - self.count)
    39         return String(self[theIndex..<endIndex])
    40     }
    41     
    42     // 截取字符串:指定索引和字符数
    43     // - begin: 开始截取处索引
    44     // - count: 截取的字符数量
    45     func subString(_ begin:Int,_ count:Int) -> String {
    46         let start = self.index(self.startIndex, offsetBy: max(0, begin))
    47         let end = self.index(self.startIndex, offsetBy:  min(self.count, begin + count))
    48         return String(self[start..<end]) 
    49     }
    50 }
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  • 原文地址:https://www.cnblogs.com/strengthen/p/10576043.html
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