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  • [Swift]LeetCode320. 通用简写 $ Generalized Abbreviation

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    Write a function to generate the generalized abbreviations of a word.

    Example:

    Given word = "word", return the following list (order does not matter):

    ["word", "1ord", "w1rd", "wo1d", "wor1", "2rd", "w2d", "wo2", "1o1d", "1or1", "w1r1", "1o2", "2r1", "3d", "w3", "4"]

    编写一个函数来生成一个单词的广义缩写。

    例子:

    给定word = "word",返回以下列表(顺序不重要):

    ["word", "1ord", "w1rd", "wo1d", "wor1", "2rd", "w2d", "wo2", "1o1d", "1or1", "w1r1", "1o2", "2r1", "3d", "w3", "4"]

    Solution:
     1 class Solution {
     2     func generateAbbreviations(_ word:String) -> [String] {
     3         var res:[String] = [String]()
     4         var str:String = String()
     5         if !word.isEmpty
     6         {
     7             str = String(word.count)
     8         }
     9         res.append(str)
    10         for i in 0..<word.count
    11         {
    12             let arr:[String] = generateAbbreviations(word.subString(i + 1))
    13             for a in arr
    14             {
    15                 var left:String = String()
    16                 if i > 0
    17                 {
    18                     left = String(i)
    19                 }
    20                 res.append(left + word.subString(i, 1) + a )
    21             }
    22         }
    23         return res        
    24     }
    25 }
    26 
    27 extension String {
    28     // 截取字符串:从index到结束处
    29     // - Parameter index: 开始索引
    30     // - Returns: 子字符串
    31     func subString(_ index: Int) -> String {
    32         let theIndex = self.index(self.endIndex, offsetBy: index - self.count)
    33         return String(self[theIndex..<endIndex])
    34     }
    35     
    36     // 截取字符串:指定索引和字符数
    37     // - begin: 开始截取处索引
    38     // - count: 截取的字符数量
    39     func subString(_ begin:Int,_ count:Int) -> String {
    40         let start = self.index(self.startIndex, offsetBy: max(0, begin))
    41         let end = self.index(self.startIndex, offsetBy:  min(self.count, begin + count))
    42         return String(self[start..<end]) 
    43     }
    44 }

    点击:Playground测试

    1 var sol = Solution()
    2 print(sol.generateAbbreviations("word"))
    3 //Print ["4", "w3", "wo2", "wor1", "word", "wo1d", "w1r1", "w1rd", "w2d", "1o2", "1or1", "1ord", "1o1d", "2r1", "2rd", "3d"]
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  • 原文地址:https://www.cnblogs.com/strengthen/p/10706726.html
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