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  • [Swift]LeetCode1081. 不同字符的最小子序列 | Smallest Subsequence of Distinct Characters

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    Return the lexicographically smallest subsequence of text that contains all the distinct characters of textexactly once. 

    Example 1:

    Input: "cdadabcc"
    Output: "adbc"
    

    Example 2:

    Input: "abcd"
    Output: "abcd"
    

    Example 3:

    Input: "ecbacba"
    Output: "eacb"
    

    Example 4:

    Input: "leetcode"
    Output: "letcod" 

    Note:

    1. 1 <= text.length <= 1000
    2. text consists of lowercase English letters.

    返回字符串 text 中按字典序排列最小的子序列,该子序列包含 text 中所有不同字符一次。 

    示例 1:

    输入:"cdadabcc"
    输出:"adbc"
    

    示例 2:

    输入:"abcd"
    输出:"abcd"
    

    示例 3:

    输入:"ecbacba"
    输出:"eacb"
    

    示例 4:

    输入:"leetcode"
    输出:"letcod" 

    提示:

    1. 1 <= text.length <= 1000
    2. text 由小写英文字母组成

    12ms
     1 class Solution {
     2 
     3     func smallestSubsequence(_ text: String) -> String {
     4         var cnt = [Int](repeating: 0, count: 26) , used = cnt
     5         var idx = 0, dic = [Character: Int](), chars = Array(text)
     6         _ = "abcdefghijklmnopqrstuvwxyz".map { dic[$0] = idx; idx += 1 }
     7         for ch in chars {
     8             let idx = dic[ch]!
     9             let ct = cnt[idx]
    10             cnt[idx] = ct + 1
    11         }
    12 
    13         var ans = ""
    14         for ch in chars {
    15             let idx = dic[ch]!
    16             let ct = cnt[idx]
    17             cnt[idx] = ct - 1
    18 
    19             let uct = used[idx]
    20             used[idx] = uct + 1
    21             if uct > 0 { continue }
    22             while !ans.isEmpty && ans.last! > ch && cnt[dic[ans.last!]!] > 0 {
    23                 used[dic[ans.last!]!] = 0
    24                 ans.removeLast()
    25             }
    26             ans += "(ch)"
    27         }
    28         return ans
    29     }
    30 }

    Runtime: 16 ms

    Memory Usage: 21.4 MB
     1 class Solution {
     2     func smallestSubsequence(_ text: String) -> String {
     3         var cnt:[Int] = [Int](repeating:0,count:26)
     4         var used:[Int] = [Int](repeating:0,count:26)
     5         var res:[Character] = [Character]()
     6         let arrText:[Character] = Array(text)
     7         let arrIndex:[Int] = Array(text).map{$0.ascii - 97}
     8         for i in arrIndex
     9         {
    10             cnt[i] += 1
    11         }
    12         for (index,i) in arrIndex.enumerated()
    13         {
    14             cnt[i] -= 1
    15             if used[i]++ > 0 {continue}
    16             while(!res.isEmpty && (res.last!.ascii - 97) > i && cnt[res.last!.ascii - 97] > 0)
    17             {
    18                 used[res.last!.ascii - 97] = 0
    19                 res.popLast()
    20             }
    21             res.append(arrText[index])
    22         }
    23         return String(res)
    24     }
    25 }
    26 
    27 //Character扩展
    28 extension Character
    29 {
    30     //Character转ASCII整数值(定义小写为整数值)
    31     var ascii: Int {
    32         get {
    33             return Int(self.unicodeScalars.first?.value ?? 0)
    34         }
    35     }
    36 }
    37 
    38 /*扩展Int类,实现自增++、自减--运算符*/
    39 extension Int{
    40     //后缀++:先执行表达式后再自增
    41     static postfix func ++(num:inout Int) -> Int {
    42         //输入输出参数num
    43         let temp = num
    44         //num加1
    45         num += 1
    46         //返回加1前的数值
    47         return temp
    48     }
    49 }
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  • 原文地址:https://www.cnblogs.com/strengthen/p/10993157.html
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