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  • [Swift]LeetCode30. 与所有单词相关联的字串 | Substring with Concatenation of All Words

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    ➤微信公众号:山青咏芝(shanqingyongzhi)
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    ➤GitHub地址:https://github.com/strengthen/LeetCode
    ➤原文地址:https://www.cnblogs.com/strengthen/p/9897592.html 
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    You are given a string, s, and a list of words, words, that are all of the same length. Find all starting indices of substring(s) in s that is a concatenation of each word in words exactly once and without any intervening characters.

    Example 1:

    Input:
      s = "barfoothefoobarman",
      words = ["foo","bar"]
    Output: [0,9]
    Explanation: Substrings starting at index 0 and 9 are "barfoor" and "foobar" respectively.
    The output order does not matter, returning [9,0] is fine too.
    

    Example 2:

    Input:
      s = "wordgoodstudentgoodword",
      words = ["word","student"]
    Output: []

    给定一个字符串 s 和一些长度相同的单词 words。在 s 中找出可以恰好串联 words 中所有单词的子串的起始位置。

    注意子串要与 words 中的单词完全匹配,中间不能有其他字符,但不需要考虑 words 中单词串联的顺序。

    示例 1:

    输入:
      s = "barfoothefoobarman",
      words = ["foo","bar"]
    输出: [0,9]
    解释: 从索引 0 和 9 开始的子串分别是 "barfoor" 和 "foobar" 。
    输出的顺序不重要, [9,0] 也是有效答案。
    

    示例 2:

    输入:
      s = "wordgoodstudentgoodword",
      words = ["word","student"]
    输出: []

    304ms
     1 class Solution {
     2     func findSubstring(_ s: String, _ words: [String]) -> [Int] {
     3         guard !words.isEmpty else {
     4             return []
     5         }
     6         guard !s.isEmpty else {
     7             return words.contains("") ? [0] : []
     8         }
     9         
    10         let string = Array(s)
    11         let wordLength = words[0].count
    12         let totalWordLength = words.count * wordLength
    13         
    14         guard totalWordLength <= string.count else {
    15             return []
    16         }
    17         
    18         let originalWordToCount = words.reduce(into: [:], { $0[$1, default:0] += 1 })
    19         
    20         var startingIndices: [Int] = []
    21         
    22         for i in 0..<wordLength {
    23             
    24             var startIndex = i
    25             var wordToCount = originalWordToCount
    26             
    27             for j in stride(from: i, to: string.count-wordLength+1, by: wordLength) {
    28                 
    29                 let word = String(string[j..<(j+wordLength)])
    30                 
    31                 if let originalCount = originalWordToCount[word] {
    32                     
    33                     while wordToCount[word] == nil {
    34                         let startWord = String(string[startIndex..<(startIndex+wordLength)])
    35                         wordToCount[startWord, default: 0] += 1
    36                         startIndex += wordLength
    37                     }
    38                     
    39                     if let currentCount = wordToCount[word] {
    40                         if currentCount == 1 {
    41                             wordToCount[word] = nil 
    42                         } else {
    43                             wordToCount[word] = currentCount - 1
    44                         }
    45                     }
    46                     
    47                     if wordToCount.isEmpty {
    48                         startingIndices.append(startIndex)
    49                         
    50                          let startWord = String(string[startIndex..<(startIndex+wordLength)])
    51                         wordToCount[startWord, default: 0] += 1
    52                         startIndex += wordLength
    53                     }
    54                     
    55                 } else {
    56                     // reset 
    57                     startIndex = j+wordLength
    58                     wordToCount = originalWordToCount
    59                 }
    60             }
    61         }
    62         
    63         return startingIndices
    64     }
    65 }

    312ms

     1 class Solution {
     2     func findSubstring(_ s: String, _ words: [String]) -> [Int] {
     3         guard !words.isEmpty else {
     4             return []
     5         }
     6         guard !s.isEmpty else {
     7             return words.contains("") ? [0] : []
     8         }
     9         
    10         let string = Array(s)
    11         
    12         let wordLength = words[0].count
    13         let totalWordLength = words.count * wordLength
    14         
    15         guard string.count >= totalWordLength else {
    16             return []
    17         }
    18         
    19         let originalWordToCount = words.reduce(into: [:], { $0[$1, default: 0] += 1 })
    20         
    21         var startingIndices: [Int] = []
    22         
    23         for i in 0..<wordLength {
    24 
    25             var startIndex = i
    26             var wordToCount: [String:Int] = [:]
    27             var wordCount = 0
    28             
    29             for j in stride(from: i, to: string.count - wordLength + 1, by: wordLength) {
    30                 
    31                 let word = String(string[j..<(j+wordLength)])
    32                 
    33                 if let originalCount = originalWordToCount[word] {
    34                     
    35                     wordToCount[word, default: 0] += 1
    36                     wordCount += 1
    37                     
    38                     while let count = wordToCount[word], count > originalCount {
    39                         let startWord = String(string[startIndex..<(startIndex+wordLength)])
    40                         wordCount -= 1
    41                         wordToCount[startWord, default: 1] -= 1
    42                         startIndex += wordLength
    43                     }
    44                     
    45                     if wordCount == words.count {
    46                         startingIndices.append(startIndex)
    47                         
    48                         let startWord = String(string[startIndex..<(startIndex+wordLength)])
    49                         wordCount -= 1
    50                         wordToCount[startWord, default: 1] -= 1
    51                         startIndex += wordLength
    52                     }
    53                     
    54                 } else {
    55                     // reset
    56                     startIndex = j+wordLength
    57                     wordToCount = [:]
    58                     wordCount = 0
    59                 }
    60             }
    61         }
    62         
    63         return startingIndices
    64     }
    65 }

    424ms

     1 class Solution {
     2     func findSubstring(_ s: String, _ words: [String]) -> [Int] {
     3         
     4         guard !words.isEmpty else {
     5             return []
     6         }
     7         guard !s.isEmpty else {
     8             return words.contains(s) ? [0] : []
     9         }
    10         
    11         let string = Array(s)
    12         let wordLength = words[0].count
    13         let totalWordLength = wordLength * words.count
    14         
    15         guard totalWordLength <= string.count else {
    16             return []
    17         }
    18         
    19         let originalWordToCount = words.reduce(into: [:], { $0[$1, default: 0] += 1 })
    20         
    21         var startingIndices: [Int] = []
    22         
    23         for i in 0..<wordLength {
    24             
    25             var startIndex = i
    26             var currentWordToCount = originalWordToCount
    27             
    28             for j in stride(from: i, to: string.count-wordLength+1, by: wordLength) {
    29                 
    30                 let word = String(string[j..<(j+wordLength)])
    31                 
    32                 if let originalCount = originalWordToCount[word] {
    33                     
    34                     while currentWordToCount[word] == nil {
    35                         let startWord = String(string[startIndex..<(startIndex+wordLength)])
    36                         startIndex += wordLength
    37                         currentWordToCount[startWord, default: 0] += 1
    38                     }
    39                     
    40                     if let currentCount = currentWordToCount[word] {
    41                         if currentCount == 1 {
    42                             currentWordToCount[word] = nil
    43                         } else {
    44                             currentWordToCount[word] = currentCount-1
    45                         }
    46                     }
    47                     
    48                     if currentWordToCount.isEmpty {
    49                         startingIndices.append(startIndex)
    50                         
    51                         // get a new combination
    52                         let startWord = String(string[startIndex..<(startIndex+wordLength)])
    53                         startIndex += wordLength
    54                         currentWordToCount[startWord] = 1
    55                     }
    56                     
    57                 } else {
    58                     // reset
    59                     startIndex = j+wordLength
    60                     currentWordToCount = originalWordToCount
    61                 }
    62             }
    63         }
    64         
    65         return startingIndices
    66     }
    67 }

    1128ms

     1 class Solution {
     2     func findSubstring(_ s: String, _ words: [String]) -> [Int] {
     3         if words.isEmpty {
     4             return []
     5         }
     6         let wordLen = words[0].count
     7         let substrLen = words.count * wordLen
     8         
     9         if s.count <  substrLen {
    10             return []
    11         }
    12 
    13         var answer = [Int]()
    14         answer.reserveCapacity(s.count)
    15 
    16         var dict = [String:Int]()
    17         for w in words {
    18             var count = 1
    19             if let v = dict[w] {
    20                 count = count + v
    21             }
    22             dict[w] = count
    23         }
    24         
    25         var i = s.startIndex
    26         let end = s.index(s.endIndex, offsetBy: -substrLen)
    27         while i <= end {
    28             if isSubstring(s[i..<s.index(i, offsetBy:substrLen)], dict, wordLen) {
    29                 answer.append(s.distance(from: s.startIndex, to: i))
    30             }
    31             i = s.index(after: i)
    32         }
    33         return answer
    34     }
    35     
    36     func isSubstring(_ s: Substring, _ words: [String:Int], _ wordLen: Int) -> Bool {
    37         var d = words
    38         var substr = s
    39         while !substr.isEmpty {
    40             let w = String(substr[substr.startIndex..<substr.index(substr.startIndex, offsetBy: wordLen)])
    41             if let c = d[w], c > 0 {
    42                 d[w] = c - 1
    43             } else {
    44                 return false
    45             }
    46             substr = substr[substr.index(substr.startIndex, offsetBy: wordLen)...]
    47         }
    48         return true
    49     }
    50 }

    1852ms

     1 class Solution {
     2     func findSubstring(_ s: String, _ words: [String]) -> [Int] {
     3         if s == nil || words.count == 0 {
     4             return []
     5         }
     6         var result: [Int] = []
     7         var dict1: [String: Int] = [String: Int]()
     8         var dict2: [String: Int] = [String: Int]()
     9         let stringLength: Int = s.count
    10         let wordsListSize: Int = words.count
    11         let wordLength: Int = words[0].count
    12         for i in 0 ..< wordsListSize {
    13             if dict1[words[i]] == nil {
    14                 dict1[words[i]] = 1
    15             } else {
    16                 dict1[words[i]]! += 1
    17             }
    18         }
    19         var s1: String
    20         var s2: String
    21         var counter1: Int
    22         var counter2: Int
    23         for i in 0 ..< wordLength {
    24             counter1 = 0
    25             counter2 = i
    26             var j = i;
    27             while j < stringLength {
    28                 s1 = s[j..<j+wordLength]
    29                 if dict1[s1] == nil {
    30                     dict2.removeAll(keepingCapacity: false)
    31                     counter1 = 0
    32                     counter2 = j + wordLength
    33                 } else if dict2[s1] == nil || dict2[s1]! < dict1[s1]! {
    34                     if dict2[s1] == nil {
    35                         dict2[s1] = 1
    36                     } else {
    37                         dict2[s1]! += 1
    38                     }
    39                     counter1 += 1
    40                 } else {
    41                     s2 = s[counter2..<counter2+wordLength]
    42                     while s2 != s1 {
    43                         dict2[s2]! -= 1
    44                         counter1 -= 1
    45                         counter2 += wordLength
    46                         s2 = s[counter2..<counter2+wordLength]
    47                     }
    48                     counter2 += wordLength
    49                 }
    50                 if counter1 == wordsListSize {
    51                     result.append(counter2)
    52                     s2 = s[counter2..<counter2+wordLength]
    53                     dict2[s2]! -= 1
    54                     counter1 -= 1
    55                     counter2 += wordLength
    56                 }
    57                 j += wordLength
    58             }
    59             dict2.removeAll(keepingCapacity: false)
    60         }
    61         return result
    62     }
    63 }
    64 
    65 private extension String {
    66     subscript (range: Range<Int>) -> String {
    67         guard let localEndIndex = self.index(self.startIndex, offsetBy: range.upperBound, limitedBy: self.endIndex) else {
    68             return String(self[self.index(self.startIndex, offsetBy: range.lowerBound)..<self.endIndex])
    69         }
    70         return String(self[self.index(self.startIndex, offsetBy: range.lowerBound)..<localEndIndex])
    71     }
    72 }

    3192ms

     1 class Solution {
     2     func findSubstring(_ s: String, _ words: [String]) -> [Int] {
     3         if words.count == 0 { return [] }
     4         let len = words[0].count
     5         
     6         let s = Array(s.characters)
     7         let concatLen = len * words.count
     8         
     9         if s.count < concatLen { return [] }
    10         
    11         // Map word to count
    12         var dict = [String: Int]()
    13         for i in 0..<words.count {
    14             let count = (dict[words[i]] ?? 0) + 1
    15             dict[words[i]] = count
    16         }
    17         
    18         var res = [Int]()
    19         for i in 0..<(s.count-words.count*len+1) {
    20             var track = [String: Int]()
    21             var ok = true
    22             let startSequence = (0..<words.count).map { i + $0 * len }
    23             for start in startSequence {
    24                 let substring = String(s[start..<start+len])
    25                 let count = (track[substring] ?? 0) + 1
    26                 if count > (dict[substring] ?? 0) {
    27                     ok = false
    28                     break
    29                 }
    30                 track[substring] = count
    31             }
    32             
    33             if ok {
    34                 res.append(i)
    35             }
    36         }
    37         
    38         return res
    39     }
    40 }

    3480ms

     1 class Solution {
     2     func findSubstring(_ s: String, _ words: [String]) -> [Int] {
     3         guard s.count > 0 && words.count > 0 else {
     4         return []
     5     }
     6     
     7     var counts = [String: Int]()
     8     words.forEach { word in
     9         counts[word, default: 0] += 1
    10     }
    11     
    12     var indices = [Int]()
    13     let ss = s.utf8CString
    14     let n = s.count
    15     let wc = words.count
    16     let len = words.first!.count
    17     for i in 0..<(n - wc * len + 1) {
    18         var seen = [String: Int]()
    19         var j = 0
    20         while j < wc {
    21             let cs = Array(ss[(i + j * len)..<(i + (j + 1) * len)]) + [0]
    22             let word = String(cString: cs)
    23             if words.contains(word) {
    24                 seen[word, default: 0] += 1
    25                 if seen[word]! > counts[word]! {
    26                     break
    27                 }
    28             } else {
    29                 break
    30             }
    31             j += 1
    32         }
    33         
    34         if j == wc {
    35             indices.append(i)
    36         }
    37     }
    38     return indices
    39     }
    40 }

    3556ms

     1  class Solution {
     2     func findSubstring(_ s: String, _ words: [String]) -> [Int] {
     3         var results:[Int] = []
     4         if s == nil || s.isEmpty || words == nil || words.isEmpty {return results}
     5         var h:[String: Int] = [String: Int]()
     6         for word in words
     7         {
     8             if h[word] == nil
     9             {
    10                 h[word] = 1
    11             }
    12             else
    13             {
    14                 h[word] = h[word]! + 1
    15             }
    16         }
    17         var len:Int = words[0].count
    18         for offset in 0..<len
    19         {
    20             var f:[String: Int] = [String: Int]()
    21             var from:Int = offset
    22             var count:Int = 0
    23             for i in stride(from: offset,through:s.count - len,by: len)
    24             {
    25                 var word:String = s.subString(i,len)
    26                 var hc:Int? = h[word]
    27                 if hc == nil
    28                 {
    29                     from = i + len
    30                     count = 0
    31                     f = [String: Int]()
    32                     continue
    33                 }
    34                 var fc:Int? = f[word]
    35                 if fc == nil
    36                 {
    37                     fc = 1
    38                 }
    39                 else
    40                 {
    41                     fc = fc! + 1
    42                 }
    43                 f[word] = fc
    44                 count += 1
    45                 while (fc! > hc!)
    46                 {
    47                     var fword = s.subString(from,len)
    48                     f[fword] = f[fword]! - 1
    49                     fc = f[word]!
    50                     from += len
    51                     count -= 1
    52                 }
    53                 if count == words.count
    54                 {
    55                    results.append(from)
    56                 }
    57             }
    58         }
    59         return results
    60     }
    61 }
    62 
    63 extension String {
    64     // 截取字符串:指定区间
    65     // - Parameter range: 闭区间
    66     // - Returns: 子字符串
    67     func subString(_ begin:Int,_ count:Int) -> String {
    68         let start = self.index(self.startIndex, offsetBy: begin)
    69         let end = self.index(self.startIndex, offsetBy: begin + count - 1)
    70         return String(self[start...end]) 
    71     }
    72 }
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  • 原文地址:https://www.cnblogs.com/strengthen/p/9897592.html
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