zoukankan      html  css  js  c++  java
  • [Swift]LeetCode68. 文本左右对齐 | Text Justification

    ★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★
    ➤微信公众号:山青咏芝(shanqingyongzhi)
    ➤博客园地址:山青咏芝(https://www.cnblogs.com/strengthen/
    ➤GitHub地址:https://github.com/strengthen/LeetCode
    ➤原文地址:https://www.cnblogs.com/strengthen/p/9923814.html 
    ➤如果链接不是山青咏芝的博客园地址,则可能是爬取作者的文章。
    ➤原文已修改更新!强烈建议点击原文地址阅读!支持作者!支持原创!
    ★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★

    Given an array of words and a width maxWidth, format the text such that each line has exactly maxWidth characters and is fully (left and right) justified.

    You should pack your words in a greedy approach; that is, pack as many words as you can in each line. Pad extra spaces ' ' when necessary so that each line has exactly maxWidth characters.

    Extra spaces between words should be distributed as evenly as possible. If the number of spaces on a line do not divide evenly between words, the empty slots on the left will be assigned more spaces than the slots on the right.

    For the last line of text, it should be left justified and no extra space is inserted between words.

    Note:

    • A word is defined as a character sequence consisting of non-space characters only.
    • Each word's length is guaranteed to be greater than 0 and not exceed maxWidth.
    • The input array words contains at least one word.

    Example 1:

    Input:
    words = ["This", "is", "an", "example", "of", "text", "justification."]
    maxWidth = 16
    Output:
    [
       "This    is    an",
       "example  of text",
       "justification.  "
    ]
    

    Example 2:

    Input:
    words = ["What","must","be","acknowledgment","shall","be"]
    maxWidth = 16
    Output:
    [
      "What   must   be",
      "acknowledgment  ",
      "shall be        "
    ]
    Explanation: Note that the last line is "shall be    " instead of "shall     be",
                 because the last line must be left-justified instead of fully-justified.
                 Note that the second line is also left-justified becase it contains only one word.
    

    Example 3:

    Input:
    words = ["Science","is","what","we","understand","well","enough","to","explain",
             "to","a","computer.","Art","is","everything","else","we","do"]
    maxWidth = 20
    Output:
    [
      "Science  is  what we",
      "understand      well",
      "enough to explain to",
      "a  computer.  Art is",
      "everything  else  we",
      "do                  "
    ]

    给定一个单词数组和一个长度 maxWidth,重新排版单词,使其成为每行恰好有 maxWidth 个字符,且左右两端对齐的文本。

    你应该使用“贪心算法”来放置给定的单词;也就是说,尽可能多地往每行中放置单词。必要时可用空格 ' ' 填充,使得每行恰好有 maxWidth 个字符。

    要求尽可能均匀分配单词间的空格数量。如果某一行单词间的空格不能均匀分配,则左侧放置的空格数要多于右侧的空格数。

    文本的最后一行应为左对齐,且单词之间不插入额外的空格。

    说明:

    • 单词是指由非空格字符组成的字符序列。
    • 每个单词的长度大于 0,小于等于 maxWidth
    • 输入单词数组 words 至少包含一个单词。

    示例:

    输入:
    words = ["This", "is", "an", "example", "of", "text", "justification."]
    maxWidth = 16
    输出:
    [
       "This    is    an",
       "example  of text",
       "justification.  "
    ]
    

    示例 2:

    输入:
    words = ["What","must","be","acknowledgment","shall","be"]
    maxWidth = 16
    输出:
    [
      "What   must   be",
      "acknowledgment  ",
      "shall be        "
    ]
    解释: 注意最后一行的格式应为 "shall be    " 而不是 "shall     be",
         因为最后一行应为左对齐,而不是左右两端对齐。       
         第二行同样为左对齐,这是因为这行只包含一个单词。
    

    示例 3:

    输入:
    words = ["Science","is","what","we","understand","well","enough","to","explain",
             "to","a","computer.","Art","is","everything","else","we","do"]
    maxWidth = 20
    输出:
    [
      "Science  is  what we",
      "understand      well",
      "enough to explain to",
      "a  computer.  Art is",
      "everything  else  we",
      "do                  "
    ]

    8ms
     1 class Solution {
     2     func fullJustify(_ words: [String], _ maxWidth: Int) -> [String] {
     3         var res:[String] = [String]()
     4         var i:Int = 0
     5         while(i < words.count)
     6         {
     7             var j:Int = i
     8             var len:Int = 0
     9             while(j < words.count && (len+words[j].count + j - i ) <= maxWidth)
    10             {
    11                 len += words[j].count
    12                 j += 1
    13             }
    14             var out:String = String()
    15             var space:Int = maxWidth - len
    16             for k in i..<j
    17             {
    18                 out += words[k]
    19                 if space>0
    20                 {
    21                     var t:Int = 0
    22                     if j == words.count
    23                     {
    24                         if j - k == 1
    25                         {
    26                             t = space
    27                         }
    28                         else
    29                         {
    30                             t = 1
    31                         }
    32                     }
    33                     //no last row
    34                     else
    35                     {
    36                         //last word
    37                         if j - k - 1 > 0
    38                         {
    39                             if space % (j - k - 1) == 0
    40                             {
    41                                 t = space / (j - k - 1)
    42                             }
    43                             else
    44                             {
    45                                 t = space / (j - k - 1) + 1
    46                             }
    47                         }
    48                         else
    49                         {
    50                             t = space
    51                         }
    52                     }
    53                     space -= t
    54                     out += String(repeating:" ",count:t)
    55                 }
    56             }
    57             res.append(out)
    58             i = j
    59         }
    60         return res
    61     }
    62 }

    8ms

     1 class Solution {
     2     func fullJustify(_ words: [String], _ maxWidth: Int) -> [String] {
     3         var result = [String]()
     4         
     5         var currentLine = [String]()
     6         var currentCount = 0
     7         var currentWordCount = 0
     8         
     9         for word in words {
    10             
    11             let wordCount = word.count
    12             
    13             if maxWidth - currentCount - currentWordCount >= wordCount {
    14                 currentLine.append(word)
    15                 currentCount += wordCount
    16                 currentWordCount += 1
    17             } else {
    18                 let lineText = makeLine(currentLine, currentCount, currentWordCount, maxWidth)
    19                 
    20                 result.append(lineText)
    21                 
    22                 currentLine = [word]
    23                 currentCount = wordCount
    24                 currentWordCount = 1
    25             }
    26         }
    27         
    28         if currentWordCount > 0 {
    29             result.append(makeLine([currentLine.joined(separator: " ")], currentCount + currentWordCount - 1, 1, maxWidth))
    30         }
    31         
    32         return result
    33     }
    34     
    35     private func makeLine(_ line: [String], _ currentCount: Int, _ currentWordCount: Int, _ maxWidth: Int) -> String {
    36         
    37         var currentLine = line
    38         
    39         let spaceNeeded = maxWidth - currentCount
    40         
    41         if currentWordCount == 1, let text = currentLine.first {
    42             return text + String(repeating: " ", count: spaceNeeded)
    43         }
    44         
    45         let spotOpen = currentLine.count - 1
    46 
    47         let spaceToAdd = spaceNeeded / spotOpen
    48         var extraSpaceToAdd = spaceNeeded % spotOpen
    49         
    50         for i in 0..<extraSpaceToAdd {
    51             currentLine[i] += " "
    52         }
    53         
    54         return currentLine.joined(separator: String(repeating: " ", count: spaceToAdd))
    55     }
    56 }

    12ms

     1 class Solution {
     2     var line: [String] = []
     3     
     4     func fullJustify(_ words: [String], _ maxWidth: Int) -> [String] {
     5         var words = words
     6         var result = [String]()
     7 
     8         while !words.isEmpty {
     9             line = []
    10 
    11             while let w = words.first, w.count + length() + line.count <= maxWidth {
    12                 line.append(words.removeFirst())
    13             }
    14 
    15             var linestring = line.removeFirst()
    16 
    17            while !line.isEmpty {
    18                 
    19                let spacer = words.isEmpty ? 1 : (maxWidth - linestring.count - length() + line.count - 1) / line.count
    20                linestring += String(repeating: " ", count: spacer) + line.removeFirst()
    21             }
    22             
    23             linestring += String(repeating: " ", count: max(0, maxWidth - linestring.count))
    24             result.append(linestring)
    25         }
    26         return result
    27     }
    28     
    29     func length() -> Int {
    30         return line.reduce(0) {$0 + $1.count}
    31     }
    32 }

     1 class Solution {
     2     func commitLine(_ words: [String], _ maxWidth: Int, _ isLastLine: Bool) -> String {
     3         var spaceCount = maxWidth
     4         for word in words {
     5             spaceCount -= word.count
     6         }
     7         
     8         var result = ""
     9         if words.count > 1 {
    10             let avgSpaceCount = spaceCount / (words.count - 1)
    11             let extSpaceCount = spaceCount % (words.count - 1)
    12             for i in 0..<words.count - 1 {
    13                 result = result + words[i] + String(repeating: " ", count: isLastLine ? 1 : (avgSpaceCount + (i < extSpaceCount ? 1 : 0)))
    14             }
    15             result += words.last!
    16             if isLastLine && (maxWidth - result.count) > 0 {
    17                 result += String(repeating: " ", count: maxWidth - result.count)
    18             }
    19         } else {
    20             result = result + words.first! + String(repeating: " ", count: spaceCount)
    21         }
    22         
    23         return result
    24     }
    25     
    26     func fullJustify(_ words: [String], _ maxWidth: Int) -> [String] {
    27         var result = [String]()
    28         var lineWords = [String]()
    29         var lineSpace = maxWidth
    30         for i in 0..<words.count {
    31             if lineSpace <= 0 {
    32                 result.append(commitLine(lineWords, maxWidth, false))
    33                 lineWords = [String]()
    34                 lineSpace = maxWidth
    35             }
    36             
    37             if words[i].count <= lineSpace {
    38                 lineWords.append(words[i])
    39                 lineSpace = lineSpace - words[i].count - 1
    40             } else {
    41                 result.append(commitLine(lineWords, maxWidth, false))
    42                 lineWords = [words[i]]
    43                 lineSpace = maxWidth - words[i].count - 1
    44             }
    45         }
    46         
    47         result.append(commitLine(lineWords, maxWidth, true)) // Commit last line
    48         return result
    49     }
    50 }
  • 相关阅读:
    用批处理来启动/停止SQL SERVER 2005的服务 【转载】
    c#命名法 【转】
    oracle 隐式游标,显示游标,游标循环,动态SELECT语句和动态游标,异常处理,自定义异常【转载】
    fetch bulk collect into 批量效率的读取游标数据 【转载】
    Oracle 外连接和 (+)号的用法 【转载】
    如何在Oracle中复制表结构和表数据 【转载】
    Oracle 小知识点
    VSS 2005 配置(含录像) 【转载】
    json 详解 【转】
    .NET 2.0 使用最新版的JSON.net 进行反序列化 【转载】
  • 原文地址:https://www.cnblogs.com/strengthen/p/9923814.html
Copyright © 2011-2022 走看看