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  • reverse-integer

    /**
    *
    * @author gentleKay
    * Reverse digits of an integer.
    * Example1: x = 123, return 321
    * Example2: x = -123, return -321
    * click to show spoilers.
    * Have you thought about this?
    * Here are some good questions to ask before coding. Bonus points for you if you have already thought through this!
    * If the integer's last digit is 0, what should the output be? ie, cases such as 10, 100.]
    * Did you notice that the reversed integer might overflow? Assume the input is a 32-bit integer, then the reverse of 1000000003 overflows.
    * How should you handle such cases?
    * Throw an exception? Good, but what if throwing an exception is not an option?
    * You would then have to re-design the function (ie, add an extra parameter).
    *
    * 整数的倒数。
    * 示例1:x=123,返回321
    * 示例2:x=-123,返回-321
    * 单击以显示扰流器。
    * 你想过这个吗?
    * 在编码之前,这里有一些好问题要问。如果你已经考虑过了,就可以给你加分!
    * 如果整数的最后一位是0,那么输出应该是什么?例如,10,100个案例。
    * 您注意到反转的整数可能溢出吗?假设输入是32位整数,则10000000003的反向溢出。
    * 你该如何处理这些案件?
    * 是否引发异常?很好,但是如果抛出异常不是一种选择呢?
    * 然后您必须重新设计函数(即,添加一个额外的参数)。
    */

    /**
     * 
     * @author gentleKay
     * Reverse digits of an integer.
     * Example1: x = 123, return 321
     * Example2: x = -123, return -321
     * click to show spoilers.
     * Have you thought about this?
     * Here are some good questions to ask before coding. Bonus points for you if you have already thought through this!
     * If the integer's last digit is 0, what should the output be? ie, cases such as 10, 100.]
     * Did you notice that the reversed integer might overflow? Assume the input is a 32-bit integer, then the reverse of 1000000003 overflows. 
     * How should you handle such cases?
     * Throw an exception? Good, but what if throwing an exception is not an option? 
     * You would then have to re-design the function (ie, add an extra parameter).
     * 
     * 整数的倒数。
     * 示例1:x=123,返回321
     * 示例2:x=-123,返回-321
     * 单击以显示扰流器。
     * 你想过这个吗?
     * 在编码之前,这里有一些好问题要问。如果你已经考虑过了,就可以给你加分!
     * 如果整数的最后一位是0,那么输出应该是什么?例如,10,100个案例。
     * 您注意到反转的整数可能溢出吗?假设输入是32位整数,则10000000003的反向溢出。
     * 你该如何处理这些案件?
     * 是否引发异常?很好,但是如果抛出异常不是一种选择呢?
     * 然后您必须重新设计函数(即,添加一个额外的参数)。
     */
    
    public class Main07 {
    	public static void main(String[] args) {
    		int x = -345;
    		System.out.println(Main07.reverse(x));
    	}
    	
    	public static int reverse(int x) {
    		StringBuilder sb = new StringBuilder(Integer.toString(x));
    		StringBuilder sb2 = new StringBuilder("-");
    		String str = "";
    		if (x >= 0) {
    			sb = sb.reverse();
    			str = sb.substring(0);
    		}else {
    			sb = sb2.append(sb.reverse());
    			str = sb.substring(0,sb.length()-1);
    		}
            return Integer.parseInt(str);
        }
    }
    

    StringBuilder:(点击,移动,放大)

    Integer:(点击,移动,放大)

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  • 原文地址:https://www.cnblogs.com/strive-19970713/p/11236572.html
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