zoukankan      html  css  js  c++  java
  • <二叉树的基本操作>

    #include<stdio.h>
    #include<stdlib.h>
    #include<string.h>
    
    #define num 100
    #define OK 1
    
    typedef int Status;
    typedef char DataType;
    
    typedef struct node
    {
        DataType data;
        struct node *lchild,*rchild;
    }BinTNode,*BinTree;
    
    Status CreateBiTree(BinTree &bt)
    {//按照先序遍历次序递归建立二叉树。
     //ABC@@DE@G@@F@@
        char ch;
        scanf("%c",&ch);
        if(ch == '@')    bt = NULL;
        else
        {
            bt = (BinTNode*)malloc(sizeof(BinTNode));
            bt->data = ch;        //生成根结点
            CreateBiTree(bt->lchild);    //构造左子树
            CreateBiTree(bt->rchild);    //构造右子树
        }
        return OK;
    }
    
    Status Inorder(BinTree bt)
    {//二叉树中序遍历非递归算法
        BinTNode *stack[num];    //定义栈数组
        int top = 0;            //初始化栈
        stack[top] = bt;
        do
        {
            while(NULL!=stack[top])
            {//扫描根结点及其所有的左结点并入栈
                top = top+1;
                stack[top] = stack[top-1]->lchild;
            }
            top = top-1;    //退栈
            if(top>=0)        //判断栈是否为空
            {
                printf("%c",stack[top]->data);    //访问结点
                stack[top] = stack[top]->rchild;    //扫描右子树
            }
        }while(top>=0);
        return OK;
    }
    
    /*
    void Vist(char ch)
    {
        printf("%c",ch);
    }
    */
    
    void PostOrder(BinTree bt)
    {//二叉树后序遍历递归算法
        if(bt)
        {
            PostOrder(bt->lchild);
            PostOrder(bt->rchild);
            printf("%c",bt->data);
        }
    
    }
    
    int Size(BinTree bt)
    {//统计二叉树中所有结点的个数
        int num1,num2;
        if(bt==NULL)
            return 0;
        else if(bt->lchild==NULL && bt->rchild==NULL)
            return 1;
        else
        {
            num1 = Size(bt->lchild);
            num2 = Size(bt->rchild);
            return (num1+num2+1);
        }
    }
    
    int LeafCount(BinTree bt)
    {//叶子结点总数为
        int LeafNum;
        if(bt==NULL)
            LeafNum = 0;
        else if((bt->lchild==NULL) && (bt->rchild==NULL))    LeafNum = 1;
        else LeafNum = LeafCount(bt->lchild)+LeafCount(bt->rchild);
        //叶子数为左右子树叶子数目之和
        return LeafNum;
    }
    
    int Depth(BinTree bt)
    {//统计二叉树深度
        int hl,hr,max;
        if(bt!=NULL)
        {
            hl = Depth(bt->lchild);    //求左子树的深度
            hr = Depth(bt->rchild);    //求右子树的深度
            max = hl>hr?hl:hr;
            return (max+1);    //返回树的深度
        }
        else
            return 0;
    }
    void Exchange(BinTree bt)
    {//交换左右二叉树
        if(bt == NULL)
            return;
        BinTNode *temp;
        temp = bt->lchild;
        bt->lchild = bt->rchild;
        bt->rchild = temp;
        Exchange(bt->lchild);
        Exchange(bt->rchild);
    }
    
    void main()
    {
        BinTree bt;
        int xz = 1;
        int yz,sd;
        while(xz)
        {
            printf("二叉树的建立及其基本操作
    ");
            printf("===========================
    ");
            printf("1,建立二叉树的存储结构
    ");
            printf("2,二叉树的基本操作
    ");
            printf("3,交换二叉树的左右
    ");
            printf("0退出系统
    ");
            printf("==========================
    ");
            printf("请选择:(0~3)
    ");
            scanf("%d",&xz);
            getchar();
            switch(xz)
            {//输入:ABC@@DE@G@@F@@@输出:CBEGDFA
            case 1:
                printf("输入二叉树的先序序列结点值:
    ");
                CreateBiTree(bt);
                printf("二叉树的链式存储结构建立完成
    ");
                printf("
    ");
                break;
            case 2:
                printf("该二叉树的后序遍历序列是:");
                PostOrder(bt);
                printf("
    ");    //输出CGEFDBA
                printf("该二叉树的中序遍历序列是:");
                Inorder(bt);
                printf("
    ");    //输出CBEGDFA
                printf("该二叉树的结点的个树是:%d
    ",Size(bt));
                yz = LeafCount(bt);
                printf("叶子结点个数是:%d
    ",yz);
                sd = Depth(bt);
                printf("该二叉树的深度是:%d
    ",sd);
                printf("
    ");
                break;
            case 3:
                Exchange(bt);
                printf("该二叉树已交换左右子树!
    ");
                printf("
    ");
                break;
            case 0:
                break;
    
            }
        }
    }
  • 相关阅读:
    UVA 10480 Sabotage (最大流最小割)
    bzoj2002 [Hnoi2010]Bounce 弹飞绵羊 (分块)
    poj3580 SuperMemo (Splay+区间内向一个方向移动)
    bzoj1500: [NOI2005]维修数列 (Splay+变态题)
    hdu3436 Queue-jumpers(Splay)
    hdu4710 Balls Rearrangement(数学公式+取模)
    hdu1890 Robotic Sort (splay+区间翻转单点更新)
    zoj2112 Dynamic Rankings (主席树 || 树套树)
    poj3581 Sequence (后缀数组)
    notepa++ Emmet的安装方法
  • 原文地址:https://www.cnblogs.com/sun-/p/4996139.html
Copyright © 2011-2022 走看看